As shown in the figure, in the pyramid p-abcd, the quadrilateral ABCD is a rectangle, the plane PCD ⊥ the plane ABCD, and M is the midpoint of PC

It is proved that: (1) connect AC, intersection BD and point O, connect OM, ∩ m is the midpoint of PC, O is the midpoint of AC, ∞ Mo ⊂ plane MDB, PA ⊄ plane MDB, ⊄ PA ⊄ plane MDB. (2) plane PCD ⊥ plane ABCD, plane PCD ∩ plane ABCD = CD, BC ⊂ plane ABCD, BC ⊥ CD, ∩ BC ⊥ plane P

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1. The perimeter of parallelogram ABCD is 70, the distances AE and AF from vertex a to BC and CD are 10 and 15, respectively
2. As shown in the figure, in the cube abcd-a1b1c1d1, P is a moving point in the side bb1c1c. If the distance from P to the straight line BC and the straight line c1d1 is equal, the curve of the trajectory of the moving point P is () A. Straight line B. circle C. hyperbola D. parabola
3. In the square abcd-a1b1c1d1, P is a moving point in the side b1b1cc. If the distance from P to the straight line BC and c1d1 is equal, then the trajectory of the moving point P is? Why a parabola?
4. In the cube abcd-a1b1c1d1, M is the midpoint of CC1. If P is on the plane of abb1a1 and satisfies ∠ pdb1 = ∠ mdb1, what is the trajectory of point P? The answer is hyperbola But I think the picture I draw also looks like a parabola Is there a curve? How can I draw only one
5. In the cube abcd-a1b1c1d1, M is the midpoint of CC1. If point P is on the plane of abb1a1 and satisfies ∠ pdb1 = ∠ mdb1, then the trajectory of point P is () A. Circle B. ellipse C. hyperbola D. parabola
6. A mathematical problem: let p be a point inside the square ABCD, and the distances from P to vertex a, B and C are 1, 2 and 3, respectively
7. P is a point inside the square ABCD. The distances from point P to vertex a, B and C are 1, 2 and 3 respectively. Find the side length of the square Using trigonometric function solution, there are two results under the solution. Why should 5-2 √ 2 be omitted?
8. Let p be a point in the square ABCD, and the distances from point P to vertex ABC are 1, 2 and 3 respectively
9. P is a point outside the parallelogram ABCD, and Q is the midpoint of PA
10. P is the point out of the plane of the parallelogram ABCD, and Q is the midpoint of PA
11. In a square pyramid p-abcd, the plane PCD is perpendicular to the plane ABCD, PC = PD = CD = 2, and the dihedral angle b-pd-c is calculated Urgent! It's a process
12. As shown in the figure, in the pyramid p-abcd, the bottom surface ABCD is a square, the PD ⊥ plane ABCD, and PD = AB = 2, e is the midpoint of Pb 1. Calculate the tangent of the angle between the paint line PD and AE 2. Verification: EF vertical plane PBC 3. Find the cosine value of dihedral angle f-pc-b
13. The difference between QA and QC
14. Two charges a and B are placed on the smooth insulating plane in vacuum, with the distance r between them. The charges are QA = + 9q, QB = + Q respectively, and another point charge QC is placed Just so that the three spheres are in equilibrium only under the action of their mutual electrostatic force, what kind of charge should QC carry, where should it be placed, and what is the amount of charge
15. What do QC, QA, QE and QD mean in quality inspection?
16. What is QC, QA, QE, and what is QB?
17. From a point m on the sphere with radius r, three pairs of perpendicular strings Ma, MB and MC of the leading sphere, then ma2 + MB2 + MC2 equals () A. R2B. 2R2C. 4R2D. 8R2
18. The square ABCD is inscribed on the circle O, P is on the inferior arc AB, connecting PD and AC to Q, and PQ = OQ Sorry, I can't draw a picture
19. Square ABCD is inscribed in circle O, P is a point on inferior arc BC, AP intersects BD with Q, QP = Qo, and QD / Qo is obtained= We haven't learned similarity and trigonometric functions yet
20. As shown in the figure, square ABCD is inscribed in ⊙ o, q is a moving point on diameter AC, connecting DQ and extending intersection ⊙ o to P. if QP = Qo, then the value of QAQC is______ ．