If the side length of the square is 2cm and the area of the overlapping part (quadrilateral abhg) is 3 / 4 times the root sign 3, what is the rotation angle

AB = Ag & nbsp; ah is the common edge, angle ABH = angle AGH = right angle & nbsp; triangle AGH is equal to triangle AGH & nbsp; triangle ABH area = 1 / 2 * quadrilateral abhg area = 1 / 2 * 4 √ 3 / 3 = 2 √ 3 / 3 & nbsp; & nbsp; & nbsp; & nbsp; BH = AB Tan (angle bah) triangle ABH area = 1 / 2 * AB * BH = 1

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1. After the square ABCD rotates n degrees around point a, the square aefg, EF and CD intersect at point o.1. Connect de and Ao, and prove that De is perpendicular to AO 2. If the side length of the square is 2 and the area of the overlapping part (quadrilateral aeod) is 4 / 3 times the root sign 3, the rotation angle n is calculated Baidu knows that there is a solution to this problem, but it uses trigonometric function Here we need to use quadrilateral or Pythagorean theorem to solve
2. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
3. Let the side length of the square ABCD be 6, and rotate 30 degrees clockwise around point a to get the square aefg, where the side FG and BC intersect at h, and find the length of BH
4. As shown in the figure, it is known that the side length of square ABCD is 10 cm, point E is on side AB, and AE = 4 cm. If point P moves from point B to point C at a speed of 2 cm / s on line BC, and point Q moves from point C to point D on line CD, let the motion time be T seconds. (1) if the motion speed of point q is equal to that of point P, after 2 seconds, are △ BPE and △ CQP identical? Please explain the reason; (2) if the velocity of point q is not equal to that of point P, then when t is the value, it can make △ BPE and △ CQP congruent; at this time, what is the velocity of point q
5. The edge CD of square ABCD connects be and DG on the edge ce of square ECGF. (1) observe the size relationship between be and DG and prove the conclusion. (2)
6. The edge CD of square ABCD connects be and DG on the edge ce of square ECGF;
7. Take a point a on De, take ad and AE as the square side, make square ABCD and square aefg on the same side, connect DG, be, then the line segment DG and be meet De De = be and DG is perpendicular to be 1. If the square aefg is rotated a degree clockwise around point a, that is, the angle bag = a degree, is the conclusion still valid 2. Let the edge length of the square ABCD and aefg be 3 and 2, and the area of the closed figure enclosed by the line segments BD, De, eg and GB be s. when a changes, does s have the maximum value? If so, calculate the maximum value of a and the corresponding value of A
8. As shown in the figure, the vertex e of the square aefg is on the edge CD of the square ABCD; the extension of ad intersects EF at the H point. (1) try to explain: △ AED ∽ EHD; (2) if e is the midpoint of CD, find the value of hdha
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11. Rotate square ABCD around point a clockwise to get square aefg. Edge FG and BC intersect at point H (as shown in the figure). Is segment Hg equal to segment HB? Please observe the conjecture first, and then prove your conjecture
12. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
13. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
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17. As shown in the figure, the quadrilateral ABCD is a square, △ ADF is rotated to get △ Abe, ∠ 1 = ∠ 2, please judge: (1) the shape of △ AEG; (2) the relationship between Ag and BG + DF
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