The edge CD of square ABCD connects be and DG on the edge ce of square ECGF. (1) observe the size relationship between be and DG and prove the conclusion. (2)

Drawing, because they are all square, BC and CD are equal, CE and CG are equal, angle BCE and angle DCG are equal to 90 degrees, triangle BCE and DCG are congruent, and be and DG are proved
Is it vertical DG?
When GD is extended to be at one point h, the angle hed = angle CGD, HDE = CDG, EHD = GCD = 90 degrees, then be is vertical to dg

RELATED INFORMATIONS

1. The edge CD of square ABCD connects be and DG on the edge ce of square ECGF;
2. Take a point a on De, take ad and AE as the square side, make square ABCD and square aefg on the same side, connect DG, be, then the line segment DG and be meet De De = be and DG is perpendicular to be 1. If the square aefg is rotated a degree clockwise around point a, that is, the angle bag = a degree, is the conclusion still valid 2. Let the edge length of the square ABCD and aefg be 3 and 2, and the area of the closed figure enclosed by the line segments BD, De, eg and GB be s. when a changes, does s have the maximum value? If so, calculate the maximum value of a and the corresponding value of A
3. As shown in the figure, the vertex e of the square aefg is on the edge CD of the square ABCD; the extension of ad intersects EF at the H point. (1) try to explain: △ AED ∽ EHD; (2) if e is the midpoint of CD, find the value of hdha
4. As shown in the figure, EF is the double fold line of square ABCD, and the vertices of ∠ A and ∠ B coincide on EF. At this time, how many degrees is ∠ DHG?
5. Two congruent squares ABCD, aefg, with vertex a, CD and EF in common, intersect at point p; PC = pf; what kind of special quadrilateral with vertex e, C, F and D needs to be proved
6. The area of square a, B, C and D is 144 square centimeters. Efgh is the middle points of four sides respectively, which are successively connected to form a small square, and the side length surface of the small square is calculated
7. ABCD is a square, the area of △ DEF is 6 square cm larger than that of △ ABF, and CD is 4 cm long
8. 22. Square ABCD, the area of triangle DEF is 6 square centimeters larger than that of triangle ABF. CD is 6 cm long, what is the length of de
9. The side length of square ABCD is 20, CD is extended to e, connecting be. If the area of triangle ABF is 30 larger than that of triangle def, the length of De is calculated
10. As shown in the figure, the quadrilateral ABCD is a rectangle, BC = 15cm, CD = 8cm. The area of triangle ABF is 30cm larger than that of triangle def. Find the length of de
11. As shown in the figure, it is known that the side length of square ABCD is 10 cm, point E is on side AB, and AE = 4 cm. If point P moves from point B to point C at a speed of 2 cm / s on line BC, and point Q moves from point C to point D on line CD, let the motion time be T seconds. (1) if the motion speed of point q is equal to that of point P, after 2 seconds, are △ BPE and △ CQP identical? Please explain the reason; (2) if the velocity of point q is not equal to that of point P, then when t is the value, it can make △ BPE and △ CQP congruent; at this time, what is the velocity of point q
12. Let the side length of the square ABCD be 6, and rotate 30 degrees clockwise around point a to get the square aefg, where the side FG and BC intersect at h, and find the length of BH
13. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
14. After the square ABCD rotates n degrees around point a, the square aefg, EF and CD intersect at point o.1. Connect de and Ao, and prove that De is perpendicular to AO 2. If the side length of the square is 2 and the area of the overlapping part (quadrilateral aeod) is 4 / 3 times the root sign 3, the rotation angle n is calculated Baidu knows that there is a solution to this problem, but it uses trigonometric function Here we need to use quadrilateral or Pythagorean theorem to solve
15. If the side length of the square is 2cm and the area of the overlapping part (quadrilateral abhg) is 3 / 4 times the root sign 3, what is the rotation angle
16. Rotate square ABCD around point a clockwise to get square aefg. Edge FG and BC intersect at point H (as shown in the figure). Is segment Hg equal to segment HB? Please observe the conjecture first, and then prove your conjecture
17. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
18. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
19. As shown in the figure, in the square ABCD, e is the midpoint of AD, f is on CD, and DF = 1 / 4CD BE.EF.BF To prove that be is perpendicular to ef
20. The square ABCD and aefg common point a point Ge rotates aefg on ADAB, whether DF and BF are equal or not, it is incorrect to give a counter example Point G is on ad, point E is on AB, connect DF and BF, rotate square aefg around point a, whether DF and BF are still equal, incorrect, give a counterexample