Rotate square ABCD around point a clockwise to get square aefg. Edge FG and BC intersect at point H (as shown in the figure). Is segment Hg equal to segment HB? Please observe the conjecture first, and then prove your conjecture

Proof: Hg = Hb, proof 1: connect ah, ∵ quadrilateral ABCD, aefg are all square, ∵ B = ≌ g = 90 °, from the title meaning know Ag = AB, ah = ah, ≌ RT △ AGH ≌ RT △ ABH (HL), ≌ Hg = Hb. Proof 2: Connect GB, ∵ quadrilateral ABCD, aefg are all square, ∵ ABC = ≌ AGF = 90 °, from the title meaning know AB = AG, ≌ AGB = ≌ ABG, ≌ HGB = ≌ HbG, ≌ Hg = Hb

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1. If the side length of the square is 2cm and the area of the overlapping part (quadrilateral abhg) is 3 / 4 times the root sign 3, what is the rotation angle
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3. As shown in the figure, rotate square ABCD around point a clockwise to get square aefg, edge FG and BC intersect at point h. verification: Hg = Hb
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