In a right triangle ABC, if AB = m and angle a = a, then the length of the high Cd on the hypotenuse ab
Tan (90-a) squared + cot (90-a) squared is 1tan (90-a) squared = ad squared / CD squared cot (90-a) squared = BD squared / CD squared = 1CD squared = ad squared + BD squared ad squared = AC squared - CD squared BD squared = BC squared - CD squared
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