As shown in the figure, △ ABC, the angle ABC = 45, ad is perpendicular to point D, be is perpendicular to point E, ad and be intersect at point h, if AC = 10, then BH=

Let BD = x, then ad = X
In △ abd, there is ab = √ 2x
In △ ADC, DC = √ (100-x2)
According to cosine theorem: cos45 ° = (AB2 + bc2-ac2) / (2Ab * BC) = (2x2 + (x + √ (100-x2)) 2-100) / (2 √ 2x (x + √ (100-x2)))
The solution is x = 10
So △ ABC is a right triangle, angle c is a right angle, so h, e, D and C coincide, BH = BC = AC = 10
Give me some points

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