As shown in the figure: in △ ABC, ad ⊥ BC is in D, be ⊥ AC is in E, ad and be intersect in H and BH = AC, find the degree of ∠ HCD

∵AD⊥BC,BE⊥AC
∴∠BDH=∠ADC
∠BHD=∠BEC
And ∵ BH = AC
∴△BHD≌△ACD
∴HD=CD
∴∠HCD=45

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