In △ ABC, D is the midpoint of AC, de ⊥ BC is e, be & sup2; - ce & sup2; = AB & sup2;, it is proved that ABC is a right triangle

In △ ABC, D is the midpoint of AC, de ⊥ BC is e, be & sup2; - ce & sup2; = AB & sup2;, it is proved that ABC is a right triangle

Bubububububu\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\bc * ce + 4ce & # 178; + AC & # 178; - 4ce & # 17