As shown in the figure, the area of △ ABC is ∠ BAC = 150 °, ab = 20cm, AC = 30cm?
Through point B as the extension of BD ⊥ AC intersection Ca at d
∵∠BAC=150
∴∠BAD=180-∠BAC=30
∵BD⊥AC
∴BD=AB/2=10
∴S△ABC=AC×BD/2=30×10/2=150(cm²)
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