Contact us
Choose a category below so we can get back to you as quickly as possible.
過點B作BD⊥AC交CA的延長線於D ∵∠BAC=150 ∴∠BAD=180-∠BAC=30 ∵BD⊥AC ∴BD=AB/2=10 ∴S△ABC=AC×BD/2=30×10/2=150(cm²;)
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.