The object with mass m = 1kg is placed on the inclined plane with an inclination angle of 37. The mass of the inclined plane is 2kg. The dynamic friction coefficient between the inclined plane and the object is 0.2. The ground is smooth. Now, a horizontal thrust is applied to the inclined plane. As shown in the figure, to make the object m relative to the inclined plane stationary, the value range of the force F? Let the maximum static friction between the object and the inclined plane equal to the sliding friction

Let A1 be the minimum acceleration that prevents the object from sliding
mgsinθ=ma1cosθ+（ma1sinθ+mgcosθ）u
A1 = 110 / 23
So the minimum f is: (M + m) A1 = 330 / 23 = 14.35n
Let A2 be the maximum acceleration that prevents the object from sliding
mgsinθ+（ma2sinθ+mgcosθ）u=ma2cosθ
a2=190/17
So the maximum f is: (M + m) A2 = 570 / 17 = 33.53n
So 14.35 f 33.53 012.3

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