Under the action of force F, an object with mass m = 10kg moves at an acceleration of a = 2m / s for 2m on the horizontal ground with dynamic friction coefficient μ = 0.2. Try to find the work done by force F on the object and the work done by the object to overcome the resistance

Under the action of force F, an object with mass m = 10kg moves at an acceleration of a = 2m / s for 2m on the horizontal ground with dynamic friction coefficient μ = 0.2. Try to find the work done by force F on the object and the work done by the object to overcome the resistance

If f-f = ma, then
And F = MGU = 100x0.2 = 20n
F=mgu+ma=20+20=40N
So: WF = FX = 80J
If work is done against resistance, if work is positive, then
Wf=fx=40J
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