The bullet with a mass of 0.02kg penetrates a fixed plank with a thickness of 10cm vertically at a speed of 600mgs. It is known that the velocity of the bullet passing through the plank is 400m/ Find the work done by the resistance of the board to the bullet (2) When an object with mass m = 1kg moves on a smooth horizontal line, the initial velocity V1 = 2m / s, and is subjected to a combined external force F = 4N in the same direction as the motion, the displacement S = 2m, what is the final kinetic energy of physics?

The bullet with a mass of 0.02kg penetrates a fixed plank with a thickness of 10cm vertically at a speed of 600mgs. It is known that the velocity of the bullet passing through the plank is 400m/ Find the work done by the resistance of the board to the bullet (2) When an object with mass m = 1kg moves on a smooth horizontal line, the initial velocity V1 = 2m / s, and is subjected to a combined external force F = 4N in the same direction as the motion, the displacement S = 2m, what is the final kinetic energy of physics?

1. Kinetic energy theorem w = 1 / 2mv0 ^ 2-1 / 2mv1 ^ 2 = 1 / 2 * 0.02 * 600 ^ 2-1 / 2 * 0.02 * 400 ^ 2 = 3600-1600 = 2000j
2. The work done by external force with initial kinetic energy 2J is 8j, and the final kinetic energy 10J is not clear