The bullet with mass m of 0.02kg vertically penetrates a fixed board with thickness s of 10cm at the speed V1 of 600m / s, It is known that the average resistance of the board to the bullet is 2x10000. What is the velocity of the bullet after passing through the board?

The bullet with mass m of 0.02kg vertically penetrates a fixed board with thickness s of 10cm at the speed V1 of 600m / s, It is known that the average resistance of the board to the bullet is 2x10000. What is the velocity of the bullet after passing through the board?

1 / 2mv1 ^ 2-2x10000 * 0.1 = 1 / 2mV ^ 2 to get v = 400m / S