A linear equation passing through point m (- 3,2) perpendicular to vector a = (- 2,1)

A linear equation passing through point m (- 3,2) perpendicular to vector a = (- 2,1)

The slope of vector a = (- 2,1) is - 1 / 2
So the slope perpendicular to it is 2
Another point (- 3,2)
y-2=2(x+3)
2x-y+8=0
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