What is the linear equation passing through point (0,4) and parallel to vector V = (2,3)?

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• 1. Find the general equations of the following plane: passing through points (3,1, - 1) and (1, - 1,0), parallel to vector V = (- 1,0,2)
• 2. Given a = (1,5, - 1), B = (- 2,3,5), if (KA + b) is parallel (a-3b), find K
• 3. Given a = (1,2), B = (- 3,2), if Ka + B is parallel to a-3b, then the value of real number k is
• 4. In △ ABC, a is an obtuse angle, Sina = 3 / 5, C = 5, B = 4
• 5. Given that the moving point P of a (- 3,8) B (7, - 4) satisfies the vector AP * vector BP = 0, then the trajectory equation of point P is
• 6. It is known that the collimator of parabola C: y ^ 2 = 4x and X-axis intersect at point m, the straight line L with slope k of point m intersects with parabola C at two points ab 1 F is the focal point of parabola C. if the module am = 5 / 4, the module AF can find the value of K 2 whether there is such a K, so that there is always Q on the parabola C, and if QA vertical QB exists, ask for the value range of K
• 7. When the straight line L passing through M (4.0) intersects the parabola C: y ^ 2 = 4x at two points a and B, 2am = MB, calculate the slope k of L RT,
• 8. Parabola y2 = 4x, slope - 2 straight line intersection parabola at a, B two points, find a, B two points distance
• 9. It is known that the parabolic equation y2 = 4x, the line L passing through the fixed point P (- 2,1) and the slope k intersect the parabolic equation y2 = 4x at two different points. The range of the slope k is obtained
• 10. Given that the parabola y ^ 2 = 4x, the points P (1,2), a (x1, Y1), B (X2, Y2) are on the parabola, when the slopes of PA and Pb exist and the inclination angles complement each other, we can find the solution Find the value of Y1 + Y2 and the slope of line ab
• 11. The point direction linear equation passing through point P (- 3,5) and parallel to vector V (5,2) is
• 12. How to use parallel vector (1,2) to get linear equation?
• 13. The linear equation parallel to vector a (2, - 3) and passing through point (1, - 2) is
• 14. A linear equation passing through point m (- 1,1) perpendicular to vector a = (2,1)
• 15. A linear equation passing through point m (- 3,2) perpendicular to vector a = (- 2,1)
• 16. A plane passing through point (2,1, - 1) and parallel to vector = (3,0,1) and = (4, - 1,2), try to find the plane equation What's the matter with vector multiplication? I'm depressed. I hope you can give me some advice The one in the middle should be 3 & nbsp; 1 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 1 & nbsp; 3 && nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2 & nbsp; 4 & nbsp; how can it be 2 & nbsp; 4?
• 17. Find the plane equation passing through point (2, - 1,4) and parallel to two vectors a = {- 3,4, - 6} and B = {- 2,3, - 1}
• 18. Let a plane pass through points m (1.0-2) and m (1.2.2) and be parallel to vector a = (1.1.1)
• 19. Solve the plane equation of (1,2,1) and (2, - 1,2) and parallel to the vector {3,2,1}
• 20. Plane equation of parallel vector (0,2, - 3) passing through point (- 1,2,0) (1,2, - 1)