When the straight line L passing through M (4.0) intersects the parabola C: y ^ 2 = 4x at two points a and B, 2am = MB, calculate the slope k of L RT,

Substituting y = K (x-4), that is, x = Y / K + 4 into y ^ 2 = 4x, we get
y^2-4y/k-16=0,
△=16/k^2+64,
From 2am = MB, 2y1 = Y2,
2 (4 / K + √ △) = 4 / K - √ △ or 2 (4 / K - √ △) = 4 / K + √ △,
√ △ = soil 4 / (3K),
1/k^2+4=1/(9k^2),
K ^ 2 = - 2 / 9, no solution

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