Given that the moving point P of a (- 3,8) B (7, - 4) satisfies the vector AP * vector BP = 0, then the trajectory equation of point P is

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• 1. It is known that the collimator of parabola C: y ^ 2 = 4x and X-axis intersect at point m, the straight line L with slope k of point m intersects with parabola C at two points ab 1 F is the focal point of parabola C. if the module am = 5 / 4, the module AF can find the value of K 2 whether there is such a K, so that there is always Q on the parabola C, and if QA vertical QB exists, ask for the value range of K
• 2. When the straight line L passing through M (4.0) intersects the parabola C: y ^ 2 = 4x at two points a and B, 2am = MB, calculate the slope k of L RT,
• 3. Parabola y2 = 4x, slope - 2 straight line intersection parabola at a, B two points, find a, B two points distance
• 4. It is known that the parabolic equation y2 = 4x, the line L passing through the fixed point P (- 2,1) and the slope k intersect the parabolic equation y2 = 4x at two different points. The range of the slope k is obtained
• 5. Given that the parabola y ^ 2 = 4x, the points P (1,2), a (x1, Y1), B (X2, Y2) are on the parabola, when the slopes of PA and Pb exist and the inclination angles complement each other, we can find the solution Find the value of Y1 + Y2 and the slope of line ab
• 6. Through the point m (2,0), make a straight line L with slope 1, intersect the parabola y * 2 = 4x at points a and B, and find the length of ab
• 7. It is known that the equation of parabola is y ^ 2 = 4x, the line L passes through the fixed point P (- 2,1), and the slope is K. when the value of K is, there is a common point between the line L and the parabola It is known that the equation of parabola is y ^ 2 = 4x, the straight line L passes through the fixed point P (- 2,1), and the slope is K. when the value of K is, the straight line L and parabola have one common point; there are two common points, but there is no common point
• 8. In the triangle ABO, vector OA = vector a, vector ob = vector B, M is the midpoint of ob, n is the midpoint of AB, P is on, the intersection of am, then what is AP equal to? Options: A 2 / 3 vector A-1 / 3 vector b B - 2 / 3 vector a + 1 / 3 vector b C 1 / 3 vector A-2 / 3 vector b D - 1 / 3 vector a + 2 / 3 vector b
• 9. In the triangle ABC, AC is 2, AB is 4, CB is 3, I is the heart, AI is XAB plus YAC, x plus y is what
• 10. I is the heart of △ ABC, AC = 2, CB = 3, Ba = 4, AI vector = XAB vector + YAC vector, then x + y =?
• 11. In △ ABC, a is an obtuse angle, Sina = 3 / 5, C = 5, B = 4
• 12. Given a = (1,2), B = (- 3,2), if Ka + B is parallel to a-3b, then the value of real number k is
• 13. Given a = (1,5, - 1), B = (- 2,3,5), if (KA + b) is parallel (a-3b), find K
• 14. Find the general equations of the following plane: passing through points (3,1, - 1) and (1, - 1,0), parallel to vector V = (- 1,0,2)
• 15. What is the linear equation passing through point (0,4) and parallel to vector V = (2,3)?
• 16. The point direction linear equation passing through point P (- 3,5) and parallel to vector V (5,2) is
• 17. How to use parallel vector (1,2) to get linear equation?
• 18. The linear equation parallel to vector a (2, - 3) and passing through point (1, - 2) is
• 19. A linear equation passing through point m (- 1,1) perpendicular to vector a = (2,1)
• 20. A linear equation passing through point m (- 3,2) perpendicular to vector a = (- 2,1)