A linear equation passing through point m (- 1,1) perpendicular to vector a = (2,1)

A linear equation passing through point m (- 1,1) perpendicular to vector a = (2,1)

Because the line is perpendicular to the vector a = (2,1)
So let the linear equation be 2x + y + C = 0
And straight line over M (- 1,1)
The linear equation is taken into account
-2+1+c=0
Then C = 1
The linear equation is 2x + y + 1 = 0