Given that A.B.C is a positive integer, what is the answer to prove that (a + b) (B + C) (c + a) is greater than or equal to 8abc

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• 1. In the triangle ABC, A.B.C is the three sides opposite to the angle A.B.C, a square - (B-C) square = BC, 1. Find the angle A 2. If BC = 2 times root sign 3, angle B is equal to X and perimeter is y, find the value range of function y = f (x)
• 2. In the triangle ABC, a, B and C are the opposite sides of angles a, B and C respectively, and satisfy b square + C square - a square = BC 1. Find the value of angle a 2. Find the value of sin (a + 15 degrees)
• 3. In △ ABC, we know that a, B and C are angles, a, B and C are opposite sides, a and B are acute angles, and cos2a = 3 / 5, SINB = 10 / √ 10 What's the math problem In △ ABC, it is known that a, B and C are angles, a, B and C are opposite sides, a and B are acute angles, and cos2a = 3 / 5, SINB = 10 / √ 10 Find the value of a + B?
• 4. In △ ABC, we know that a, B and C are angles, a, B and C are opposite sides, a and B are acute angles, and cos2a = 3 / 5, SINB = 10 / √ 10, C = √ In △ ABC, it is known that a, B and C are angles, a, B and C are opposite sides, a and B are acute angles, and cos2a = 3 / 5, SINB = 10 / √ 10 C = √ 5 for ABC area
• 5. It is known that a, B and C are the three sides of △ ABC. It is proved that | a + B-C | + | a-b-c | = 2B Such as the title
• 6. The length of the three sides of a triangle is ABC. If a and B are equal to 10, AB is equal to 18, and C is equal to 8, judge the shape of the triangle,
• 7. If three sides a, B and C of triangle ABC satisfy (a-b): (C-B): (a + b) = 7:1:18, the shape of the triangle is judged There is a reasoning process
• 8. If the three sides a, B and C of a triangle are suitable for A2 (B-C) + B2 (C-A) + C2 (a-b) = 0, then the shape of △ ABC is () A. Right triangle B. isosceles triangle C. isosceles right triangle D. equilateral triangle
• 9. If A-B = 5, the square of a + the square of B = 17, then AB = a + B=
• 10. (1 + 2 + 3 + 4 +... + 98 + 99 + 100) / 5 is equal to?
• 11. (a + b) * (B + C) * (a + C) greater than or equal to 8abc
• 12. It is proved that (a + b) (B + C) (c + a) is greater than or equal to 8abc, and (a, B, c) are positive real numbers
• 13. Proof: if ABC is positive, then (a + b) (B + C) (c + a) > = 8abc Online solution, get rid of~~
• 14. How to prove that (A's square + 1) times (B's square + 1) times (C's square + 1) is greater than or equal to 8abc
• 15. Positive numbers a, B, C satisfy a + B + C-2 = 0, and prove that (2-A) (2-B) (2-C) is greater than or equal to 8abc
• 16. Prove the inequality, if a, B, C are all positive numbers, then (a + b) (B + C) (c + a) ≥ 8abc
• 17. If a, B and C are all positive numbers, then (a + b) (B + C) (c + a) > = 8abc
• 18. In the triangle ABC, if three sides are known to be continuous positive integers, The cosine value of the maximum angle is - 1 / 4. Find the maximum area of the parallelogram with the maximum angle as the inner angle and the sum of the two sides of the angle as 4
• 19. It is known that the lengths of a, B and C on three sides of a triangle ABC are integers, and a is less than or equal to B and less than or equal to C. If b = m (m ∈ positive integer), then such a triangle has I know the answer is m (M + 2) / 2, but I don't know why There are several (in M)
• 20. In △ ABC, the lengths of three sides are positive integers a, B and C respectively, and C ≥ B ≥ a > 0. If B = 4, then such triangles have the same length______ One