If the three sides a, B and C of a triangle are suitable for A2 (B-C) + B2 (C-A) + C2 (a-b) = 0, then the shape of △ ABC is () A. Right triangle B. isosceles triangle C. isosceles right triangle D. equilateral triangle

The original formula = a2b-a2c + b2c-a22 + C2 (a-b) = AB (a-b) - C (a + b) (a-b) + C2 (a-b) = (a-b) [c2-c (a + b) + AB] = (a-b) (C-A) (C-B), that is, (a-b) (C-A) (C-B) = 0, so a = B or C = a or C = B, so △ ABC is an isosceles triangle

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