3x & # 179; Y & # 179; * (- 3 / 2x & # 178; y) & # 179; + (- 1 / 3x & # 178; y) & # 179; * 9xy & # 178; when x = - 1, y = - 2 3x³y³*(-2/3x²y)³+(-1/3x²y)³*9xy²

3x & # 179; Y & # 179; * (- 3 / 2x & # 178; y) & # 179; + (- 1 / 3x & # 178; y) & # 179; * 9xy & # 178; when x = - 1, y = - 2 3x³y³*(-2/3x²y)³+(-1/3x²y)³*9xy²

The original formula = 3x & # 179; Y & # 179; (- 8 / 27x6y & # 179;) + (- 1 / 27x6y3) 9xy & # 178;
=-8/9x9y6-1/3x7y5
=-8/9（-1）9（-2）6-1/3（-1）7（-2）5
=512/9-32/3
=512/9-96/9
=416/9

3x & # 179; Y & # 179; · (- 2 / 3x & # 178; y) & # 178; + (- 1 / 3x & # 178; y) & # 179; · 9xy & # 178;), where x = - 1, y = 2 is reduced before evaluation

This is the last time we will be 179; y \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\y ^ 5 = 1 / 9 * x ^ 7Y ^ 5 ∵ x = - 1, y = 2 ∵ original formula = 1 / 9 * (- 1) * 32 = - 32 /

How about (X & # 178; + 6x + 6) &# 178; + X & # 178; + 6x + 4, X & # 8308; - 2x & # 179; - 8x + 16

Interesting, but I don't know what you want to be and what kind of result you want to achieve

It is known that the quadratic function y = (M + 1) x ^ 2 / 2 - (3m + 1) x / 2 + m, and the ordinate of the intersection point with the Y axis is m, m ≠ 1
If the image section line of quadratic function y = - x + 1, the length of the line is 2 √ 2, the value of M is determined

Let two intersection points of quadratic function and straight line be a (x1, Y1), B (X2, Y2)
Then Y1 = - X1 + 1, y2 = - x2 + 1
AB^2=(X1-X2)^2+(Y1-Y2)^2
Y1-Y2=-X1+1+X2-1=X2-X1
(Y1-Y2)^2=(X2-X1)^2=(X1-X2)^2
So AB ^ 2 = (x1-x2) ^ 2 + (y1-y2) ^ 2 = 2 (x1-x2) ^ 2 = 2 √ 2 ^ 2 = 8
(x1-x2) ^ 2 = 4
(X1+X2)^2-4X1X2=4
Simultaneous y = (M + 1) x ^ 2 / 2 - (3m + 1) x / 2 + m and y = - x + 1
(m+1)x^2/2-(3m+1)x/2+m=-x+1
(m+1)x^2/2-（3m-1）x/2+m-1=0
x1+x2=（3m-1）/(m+1)
x1x2=2(m-1)/(m+1)
Substituting the above formula
（3m-1）^2/(m+1)^2-8(m-1)/(m+1)=4
m=-5 or 1/3
Because delta > 0
So ((3m-1) / 2) ^ 2-4 * (M + 1) / 2 * (m-1) > 0
M^2-6M+9＞0
M≠3
So m = - 5 or 1 / 3

The sum of the three digits obtained by reversing the order of the three digits is 1171

437 decision is right

F (x) = the third power of X + X, if X1 + x2

F (x) = the third power of X + x = x + x ^ 3,
Then f (- x) = - x-x ^ 3 = - f (x),
So the function is odd
Because the functions X and x ^ 3 are increasing functions on R,
So f (x) is an increasing function of R
Because X1 + x2 ＜ 0, x1 ＜ - X2,
And the function f (x) is an odd function and an increasing function on R,
So f (x1)

Solution equation: 13x-5x = 12.8

13x-5x=12.8
8x=12.8
x=1.6

It is known that the right focus of the ellipse e: x2 / A2 + Y2 / B2 = 1 (a > b > 0) is f (3,0). If the coordinates of the midpoint of a and B are (- 1,1), then the intersection of E and a, B is smooth
The equation is
Is there a simple method? Can parametric equation be solved?

Let a (x1, Y1), B (X2, Y2) X1 ^ 2 / A ^ 2 + Y1 ^ 2 / b ^ 2 = 1.1 formula x2 ^ 2 / A ^ 2 + Y2 ^ 2 / b ^ 2 = 1.2 formula 2-1 formula (x2-x1) (x2 + x1) / A ^ 2 + (y2-y1) (Y2 + Y1) / b ^ 2 = 0ab, and the midpoint coordinate is (- 1,1)} x2 + X1 = - 2Y2 + Y1 = 2y2-y

Just learn the principle of computer composition ask for help the problem of complement addition and subtraction: x = + 1101, y = + 0110, find X-Y
Computer composition principle complement addition and subtraction problem: x = + 1101, y = + 0110, find X-Y, question: (1) the result is X-Y = + 0111, but according to the overflow detection of single sign bit, the highest bit of numerical value and the carry of sign bit are 11 (no overflow is negative) why the final answer is positive
(2) X = + 1100, y = + 1000, find x + y. The result of this question overflows. Can the result of X + y be expressed? If so, how to express it
Note: fixed point addition and subtraction

Before discussing overflow or no overflow, we should explain the word length
Determine the length of the word, you can determine the number range represented by the complement
Then, these numbers + 1101 and + 0110 are changed into complements, and then they are calculated and judged

Calculation (1 + 3 + 5 + 7 +2013）-（2+4+6… +2012）=______ ．

（1+3+5+7… +2013）-（2+4+6… +2012）=（1+2013）×[（2013-1）÷2+1]÷2-（2012+2）×[（2012-2）÷2+1]÷2，=2014×[2012÷2+1]÷2-2014×[2010÷2+1]÷2，=2014×1007÷2-2014×1006÷2，=1007×1007-1007×1006...