Given X & # 178; + X-1 = 0, then x & # 179; + 2x & # 178; - 3=

Given X & # 178; + X-1 = 0, then x & # 179; + 2x & # 178; - 3=


x²+x-1=0
x²+x=1
be
x³+2x²-3
=x³+x²+x²-3
=x(x²+x)+x²-3
=x+x²-3
=1-3
=-2



What is the solution of (X-Y) & # 178; · (Y-X) & # 179; · (Y-X) & # 178
(x-y)²·(y-x)³·(y-x)²,


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Solve the equations (1) 3A + B / 2 = 1A / 3, a-3b = 2 (2) x / 2-y / 3 = 4, X / 3 + Y / 6 = 5


(1)3a+b/2=1a/3,a-3b=2
The results are as follows
7a+3b=0 ①
a-3b=2 ②
① + 2
8a=2
∴a=1/4
b=11/4
(2)x/2-y/3=4,x/3+y/6=5
The results are as follows
3x-2y=24 ①
4x+2y=60 ②
① + 2
7x=84
∴x=12
y=6



It takes 7 hours for a freight car to go from place a to place B, and 9 hours for a bus to go from place B to place a. the two cars leave from both places at the same time. The freight car stops for 2 hours on the way for some reason. When they meet, the bus travels 30 kilometers more than the freight car. How many kilometers are there between Party A and Party B?


(1-19 × 2) / (17 + 19) = (1-29) / - 1663 = 79 / 1663 = 3116 (hours). 30 / [(1-17 × 4916) - 17 × 4916] = 30 / [(1-716) - 716] = 30 / [916-716] = 30 / 216 = 240 (km). A: the distance between Party A and Party B is 240 km



A few plus seven thirds is five


5 = 15 / 3, 8 / 3



A and B two cars from a, B two opposite, if B first two hours after a departure, two cars just meet at the midpoint, if a car
The speed is 50 km / h. The speed of car B is 45 km / h. how many km did car a travel when they met?
The key is that the fourth grade doesn't learn equation. Is there any other way to calculate it?


The distance that B travels before a is 45 × 2
A travels 50-45 miles per hour more than B
Because it is the middle point meeting, that is, the distance a and B take is the same
Therefore, the driving time of a is 45 × 2 (50-45) = 18 hours
So car a drove [45 × 2 ÷ (50-45)] × 50 = 900 km



The solution of equation 1 / X-1 = 3 / 2x + 3 is


Multiply by (x-1) (2x + 3)
2x+3=3x-3
x=6
By testing, x = 6 is the solution of the equation



Given that three points a (2,2), B (1,3) and C (- 1, m) in the plane are collinear, find the value of M and find the concrete value


m=5
Because the three points in the plane are collinear, we can use the vector parallel method
Because a, B and C are collinear
So vector AB / / vector BC
In terms of coordinates, it is (- 1,1) / / (- 2, M-3)
From vector parallelism: - 2 = 3-m
So m = 5



Careless Wang Chao forgot to write the decimal point when he wrote a two digit number. As a result, the integer he got was 44.55 larger than the original decimal. What was the original two digit number?


0.45 ah ha ha, you see 0.45 does not write decimal point is 45 No, then 45-0.45 = 44.55



A and B start from a and B at the same time. For the first time, they meet at 80 km away from A. after meeting, they continue to move forward and return immediately after reaching the destination. For the second time, they meet at 60 km away from B. find the distance between a and B


A: the distance between a and B is 180 km