M {a B C} is the average of ABC and min {a B C} is the minimum of ABC M {a, B, C} is the average of ABC, min {a, B, C} is the minimum of ABC If M {a, B, C} = min {a, B, C}, then a = b = C Then, on the same function image, draw the image of y = x + 1, y = 2-x, y = (x-1) & sup2 Judge by image What is the maximum value of Min {x + 1,2-x, (x-1) & sup2;}? I know the answer is 1 So please talk about the process Correct answer = 0=

M {a B C} is the average of ABC and min {a B C} is the minimum of ABC M {a, B, C} is the average of ABC, min {a, B, C} is the minimum of ABC If M {a, B, C} = min {a, B, C}, then a = b = C Then, on the same function image, draw the image of y = x + 1, y = 2-x, y = (x-1) & sup2 Judge by image What is the maximum value of Min {x + 1,2-x, (x-1) & sup2;}? I know the answer is 1 So please talk about the process Correct answer = 0=


x+1



Judge whether an element belongs to a matrix
In MATLAB, is there a function that can directly judge whether a number belongs to a matrix? If not, how to judge


I don't know if you mean to judge whether there is an element in a matrix whose value is a certain number
Any (x = = a). If one or more values in X are a, 1 is returned, otherwise 0



If the point representing the number x on the number axis is on the left side of the origin, what is the result of simplifying | 3x + √ X & #?
When a ≤ 0, B < 0, √ AB & # 179; =?


|3x+√x²| = |3x - x | = - 2x



Finding monotone interval of function: (1) y = sin (π / 4-3x), (2) f (x) = SiNx (SiNx cosx)


(1)y=sin(π/4-3x)
Increasing 2K π - π / 2



If (XM ﹣ X2N) 3 ﹣ x2m-n and 2x3 are of the same kind, and M + 5N = 13, find the value of m2-25n


(XM ﹣ X2N) 3 ﹣ x2m-n = (xm-2n) 3 ﹣ x2m-n = x3m-6n ﹣ x2m-n = xm-5n, because it is the same as 2x3, so m-5n = 3, M + 5N = 13, ﹣ M = 8, n = 1, so m2-25n = 82-25 × 12 = 39



It is known that f (x) = log2 x + 2 x belongs to the range of [1,16] to find y = F2 (x) + F (x2)


Log2 x monotone increasing, 2x monotone increasing ﹥ f (x) = log2 x + 2 x ∈ [1,16] monotone increasing [f (x)} ^ 2 monotone increasing, f (x ^ 2) monotone increasing ﹥ y = {f (x)] ^ 2 + F (x ^ 2) monotone increasing Ymin = [f (1)] ^ 2 + F (1) = [log2 1 + 2 * 1] ^ 2 + [log2 1 ^ 2 + 2 * 1 ^ 2] = 2 ^ 2 + 2 = 6ymax = [f (16)] ^ 2 + F (16 ^ 2) = [log2 16



-X ^ 2 + 2x x ≤ 0 ln (x + 1) x > 0 | f (x) | ≥ ax, then the value range of a
-x^2+2x x≤0 ; ln(x+1)x>0 ,
If | f (x) | ≥ ax, then the value range of a is


| f(x)|=x^2-2x.(x≤0)
            =ln(x+1).(x>0)
(1) When a = 0
|F (x) | constant & gt; = 0, holds
(2) When a & gt; 0
When x ≤ 0
|F (x) | = x ^ 2-2x constant & gt; = ax
X & gt; 0
| f(x)|=ln(x+1)
There are always moments when y = ax and ln (x + 1) intersect, so | f (x) | constant & gt; = ax is not satisfied
(3) When a & lt; 0
X & gt; 0
|F (x) | = ln (x + 1) constant & gt; = ax
When x ≤ 0
| f(x)|=x^2-2x
f'(x)=2x-2
In order to satisfy | f (x) | constant & gt; = ax
∴f'(x)=2x-2≤a.(x≤0)
∴-2≤a<0
In conclusion, the value range of a: - 2 ≤ a ≤ 0



Why is a function bounded if it has a limit?
Like the title,


Let the limit of this function at x0 be x1, then for any E > 0, there exists a > 0, any 0



1. Prove: if a and B are symmetric matrices of the same order, then AB is also symmetric if and only if a and B are commutative, that is, ab = Ba 2. Prove: let a be odd


Because a and B are symmetric matrices of the same order, a '= a, B' = B
So there are
AB is a symmetric matrix
(AB)' = AB
B'A' = AB
BA = AB
A. B exchangeable



What are the plural words that can go to f and add ves or directly add s


There are not many plural nouns ending with f or Fe, so they can be summarized into the following three types. Basically, you can recite them. There are no rules to find, so it depends on your memory. These include the usages you need in daily life