For example: m {- 1, 2, 3} = − 1 + 2 + 33 = 43; min {- 1, 2, 3} = - 1; min {- 1, 2, a} = a (a ≤− 1) − 1 (a >− 1) solve the following problem: (1) fill in the blanks: if min {2, 2x + 2, 4-2x} = 2, then the value range of X is______ (2) if M {2, x + 1, 2x} = min {2, x + 1, 2x}, find X

For example: m {- 1, 2, 3} = − 1 + 2 + 33 = 43; min {- 1, 2, 3} = - 1; min {- 1, 2, a} = a (a ≤− 1) − 1 (a >− 1) solve the following problem: (1) fill in the blanks: if min {2, 2x + 2, 4-2x} = 2, then the value range of X is______ (2) if M {2, x + 1, 2x} = min {2, x + 1, 2x}, find X


(1) This is the answer: 0 ≤ x ≤ 1 (2) m {(2) m {(2) m {2, x + 1, x + 1, 2x} = 2 + X + 1 + 2x3 = x + 1. Method 1: when x ≥ 1, then min {2, X + 1, 2x} = 2, then x + 1 = 2, then x + 1 = 2, then x + 1 = 2, x = 1. When x < 1, when x < 1, when x < 1, when min {2, min {2, x + 2, x + 2, x + 1, 2x} = 2x, then x + 1 = 2x, then x + 1 = 2x, x = 1 (omitted). The above is: x = 1. Method 2: x = 1. Method 2: Method 2: This is the second: the second: the second: the second is the second: the second is the second: x = 1. Method 2: the second is the second: the second: the second: x + 12x ≥ x + 1 ,∴x≤1x≥1,∴x=1.



For three numbers a, B, C, m {a, B, C} denotes three average numbers, min {a, B, C} denotes the least decimal 1 of a, B, C, min {100101,10}=


10



I want to ask a question: given the points P (8, - 2), q (3, n), and PQ is parallel to the X axis, then n=-


N=-2



The minimum positive period of the algebraic sum of several sine and cosine functions is equal to
The least common multiple of the numerator of the least positive period of each function divided by the greatest common divisor of the denominator
Why?


This algorithm is not necessarily correct (if there are high-order or absolute values), it is best to draw



If the line L is parallel to the line 2x + Y-3 = 0 and the intercept on the X axis is - 2, then the equation of the line l?


2X+y-3=0
y=-2x+3
parallel
So y = - 2x + B
The intercept on the X axis is - 2
Then x = - 2, y = 0
So 0 = 4 + B
b=-4
So 2x + y + 4 = 0



4.58 + 25.1 + 45.8 × 6.35 + 8.458 × 114 (simple operation)


4.58×25.1+45.8×6.35+0.458×114
=45.8×2.51+45.8×6.35+45.4×1.14
=45.8×(2.51+6.35+1.14)
=45.8×10
=458



The straight line y = KX + B is parallel to the straight line y = (2-x) / 3 and intersects with the straight line y = - (2x-1) / 3 at the same point on the y-axis


Because y = KX + B is parallel to the straight line y = (2-x) / 3, so the slope is equal, that is, k = - 1 / 3. And it intersects with the straight line y = - (2x-1) / 3 at the same point on the Y axis, so we can make x = 0, and we can get the intersection coordinate as (0,1 / 3). Because y = KX + B passes through this point, so B = 1 / 3, so the straight line is y = - 1 / 3x + 1 / 3



Given that a belongs to R, find the monotone interval of function FX = x ^ 2E ^ ax


F(x)=x^2e^(ax)
F '(x) = e ^ (AX) + ax & sup2; e ^ (AX)
= e^(ax)( ax²+2x)
E ^ (AX) is always greater than 0
① When a > 0, ax & sup2; + 2x > 0, the solution is x > 0 or X



The water depth of a water area is 8 meters, and the distance between the moon and the earth is 3.84 × 10 5 km. What is the distance between the image of the moon in the river and the surface of the lake?


5 km of 3.84 * 10



To solve the inequality with parameter (1) 56x square + ax-a square


(1)(7x+a)(8x-a)<0
If a = 0, it becomes 56x & sup2; < 0, and there is no solution
a> 0, the solution set is - A / 7