Let a ∈ r solve the inequality about X: AX2 - (a + 1) x + 1 Let a ∈ r solve the inequality about X: AX2 - (a + 1) x + 1

Let a ∈ r solve the inequality about X: AX2 - (a + 1) x + 1 Let a ∈ r solve the inequality about X: AX2 - (a + 1) x + 1

ax2-(a+1)x+1=（ax-1）（x-1）;
Discussion according to the situation:
one

The solution of the inequality AX2 - (a + 1) x + 1 > 0 (a ≠ 0) about X

Original inequality = a (x-1) (x-1 / a) > 0
1) When 0

Solution to x inequality AX2 - (a + 1) x + 1

When a = 0, we get - x + 11
When a ≠ 0, (AX-1) (x-1) is obtained

Finding the number of zeros of function f (x) = x ^ 2-4x + 3 on (2,5)

Let f (x) = 0, take the value of X at this time, which is zero
Then x ^ 2-4x + 3 = 0 (x-3) (x-1) = 0,
So x = 3, or x = 1
And because it is the zero point on (2,5), the number of zeros is one, that is, when x = 3
I also answered the previous question, don't you see?

Simple mathematical simple calculation problem:
17.48×37-174.8×1.9+17.48×82
（1+1.2）+（2+1.2×2）+（3+1.2×3）+…… +（99+1.2×99）+（100+1.2×100）

The first question: 17.48 × 37-174.8 × 1.9 + 17.48 × 82 = 17.48 × 37-17.48 × 19 + 17.48 × 82 = 17.48 × (37-19 + 82) = 17.48 × 100 = 1748 the second question: (1 + 1.2) + (2 + 1.2 × 2) + (3 + 1.2 × 3) + +（99+1.2×99）+（100+1.2×100）=(1+2++…… +10...

Given that the function f (x) = KX ^ 3 + 3 (k-1) x ^ 2-k ^ 2 + 1 (k > 0) is a decreasing function on (0,4), the value range of real number k is obtained
The answer is probably to find X1 and X2 after derivation, and then use Weida's theorem X1 + x2 > 4 to solve it
My question 1: can we discuss the size of x1.x2 after finding X1 and X2, and use x24 when x1x2?
My question 2: when can we use this method to solve the problem? In case what (2,4) instead of (0,4) can we use this method to solve this problem?

This problem does not require a specific solution, but should use the derivative function g (x) image
G (x) is a quadratic function with opening upward, as long as it is constant negative at (0,4)
That is g (0)

As shown in the figure, in the triangular prism abc-a1b1c1, the side abb1a1 and acc1a1 are all square, with ∠ BAC = 90 ° and D as the midpoint of BC. (I) verification: A1B ‖ plane ADC1; (II) verification: C1a ⊥ B1C

Because acc1a1 is a square, so o is the midpoint of A1C, and D is the midpoint of BC, so od is the median line of △ a1bc, so A1B ‖ OD. Because od ⊂ plane ADC1, A1B ⊄ plane ADC1, so A1B ‖ plane ADC1

What is the formula of Newton's second law?

Newton's second law expression: F = ma, where f is the combined external force on the object, M is the mass of the object, and a is the acceleration generated by the moving object

3x-8+2x+6=18

5x-2=18
x=4

4. The circumference of a rectangle is 96cm. If the length is reduced by 1 / 7 and the width is increased by 1 / 5, it will become a square and find the area of the original rectangle
Please use arithmetic, use equation, anyone can, I just want to use arithmetic! Use equation, I only use arithmetic!

96 divided by 2 is 48
Length 28 width 20 7:5 equals 28:20
28 times 20 equals 560