The formula 1 / 2mV ^ 2 = MGH is suitable for the experimental conditions

The formula 1 / 2mV ^ 2 = MGH is suitable for the experimental conditions

An object moves at an initial velocity of 0 under the action of gravity only

-MGH = 1 / 2mV ^ 2 or MGH = 1 / 2V ^ 2
Why? Lift something up from a standstill. Gravity does negative work.
Is the formula 0-1 / 2mV ^ 2 = - MGH?

For this state, it's end of e-beginning of E = - MGH
1/2mv^2-0=-mgh

What does w = MGH ask for? What do these letters mean? What's the difference between w = MGH and w = FS,

W = MGH, this is the work done by gravity, W is the work, m mass, g = 9.8n/kg (1kg object under gravity is 9.8N) H is the distance (height) in the direction of gravity, w = FS, W is the work, F, the force to do the work, s, the distance in the direction of F. these two actually have the same meaning, you see w = MGH = GHW = fs (g, f both

The root of the equation MX2 + x-2m = 0 (m ≠ 0) is______ ．

The root of equation MX2 + x-2m = 0 (m ≠ 0), the root of equation MX2 + x-2m = 0 (m ≠ 0), the root of equation MX2 + x-2m = 0 (m ≠ 0), the root of equation b2-4ac = 1-4m × (- 2m) = 1 + 8m2, ∵ 8m2 ≥ 0, the root of equation MX2 + x-2m = 0 (m ≠ 0) is two unequal real roots

There is a point P on the ellipse x2 / A2 + Y2 / B2 = 1 (a > b > 0), so that OP ⊥ AP (o is the origin, a is the endpoint of the long axis), and the range of the eccentricity of the ellipse is

This topic has done, the direct screenshot gave you, above has added the annotation to you

1 / 2 1 / 4 1 / 8 1 / 16 = 18, plus operation symbol
18 to 8

Er, er. Test the IQ, isn't it. (1 / 4 ﹣ 1 / 2) ﹣ 1 / 8-1 / 16)
=1/2÷1/16
=8

When a is a, the solution of equation 3 (5x-6) = 3-20x is also the solution of equation A-3 / 10x = 2A + 10x
When a is a, the solution of equation 3 (5x-6) = 3-20x is also the solution of equation A-3 / 10x = 2A + 10x

3(5x-6)=3-20x
15x-18=3-20x
35x=21
x=3/5
Put it in another equation
(a-3)/(10×3/5)=2a+10×3/5
(a-3)/6=2a+6
a-3=12a+36
11a=-39
a=-39/11

Given that the sum of the distances from a point on the ellipse to two focal points (0,4), (0, - 4) is equal to the root sign 13, then the length of the short half axis of the ellipse is

The sum of the distances from a point on the ellipse to two focal points is equal to the length of the major axis,
That is, 2A = 4 √ 13
a=2√13
And because C = 4
So B & # 178; = A & # 178; - C & # 178; = 52-16 = 36
b=6
The length of the short half axis is 6

3.6 ÷ [0.25 × (17.3 + 30.7)] how to operate easily

3.6÷【0.25×4×12】=3.6÷12=0.3

What is the speed zero seven minus six equal to zero three plus four,

0.7x-6＝0.3x+0.4
x=16