A number is 0.15 greater than 2% of 18.5. What is the number? Use the equation to solve

A number is 0.15 greater than 2% of 18.5. What is the number? Use the equation to solve

Let this number be X
x-18.5×2%=0.15
x-0.37=0.15
x=0.52

It is known that the equation of circle C is the square of X + the square of y = the square of R. prove that the tangent equation passing through a point m (x0, Y0) on circle C is the square of x0x + y0y = R

The circle C is x ^ 2 + y ^ 2 = R ^ 2, so the circle passes through the origin, and the radius is r to connect OM, then | om | = R let the tangent through M (x0, Y0) be l, then OM is perpendicular to L. take any point n (x, y) on the tangent L in the right triangle omn, on ^ 2 = om ^ 2 + Mn ^ 2 = R ^ 2 + Mn ^ 2on ^ 2 = x ^ 2 + y ^ 2. According to the distance formula between two points, Mn ^ 2 = (x-x0) ^ 2 + (y-y0

Given y = √ x ^ 2-4 + √ 4-2 ^ 2 + x ^ + X + 8 / 2 + X. find the value of X √ y + y √ X - √ 56

y=√(x^2-4)+√(4-x^2)+(x^2+x+8)/(2+x)
∵x^2-4≥0,4-x^2≥0,x+2≠0
∴x^2-4=0,x≠-2
x=2
y=0+0+(2^2+2+8)/(2+2)=7/2
x√y+y√x-√56=2√(7/2)+7/2√2-2√14=7/2√2-√14

What is Tan 45?

1

In a right angle trapezoid ABCD, ad is parallel to BC angle ABC = 90 degree ad = AB = 3 BC = 4 P moves along BC to C, Q starts from d along Da, passes through Q, is perpendicular to ad, BC and N PQ simultaneously
Finding the length of NC MC

(1) In rectangular trapezoid ABCD,
∵ QN ⊥ ad, ∠ ABC = 90 °, the quadrangle abnq is a rectangle
∵QD=t,AD=3,∴BN=AQ=3-t,∴NC=BC-BN=4-（3- t）= t+1.
∵AB＝3,BC＝4,∠ABC＝90°,∴AC=5.
∵QN⊥AD,∠ABC＝90°,∴MN‖AB,∴△MNC∽△ABC,
That is, MC = 5T + 1 / 4
(2) When QD = CP, the quadrilateral pcdq forms a parallelogram
When t = 4-T, i.e. t = 2, the quadrilateral pcdq forms a parallelogram
(3)∵MN‖AB,
In order to make QN divide the area of △ ABC equally, the area ratio of △ MNC to △ ABC is 1:2, that is, the similarity ratio is 1:, ■, i.e., t =. CN =, MC =, CN + MC =, ∫ half of the circumference of ∫ ABC = = 6 ≠, and there is no time when QN divides the area and circumference of △ ABC equally
(4) There are three cases
① As shown in the figure, when PM = MC, △ PMC is an isosceles triangle
Then PN = NC, namely 3-t-t = t + 1,
At the same time, △ PMC is an isosceles triangle
② As shown in the figure, when cm = PC, △ PMC is an isosceles triangle
That is,
Δ PMC is an isosceles triangle
③ As shown in the figure, when PM = PC, △ PMC is an isosceles triangle
∵PC=4－t,NC=t+1,
∴PN=2t-3,
Again,
∴MN= ,
From the Pythagorean theorem, we can get [] 2 + (2t-3) 2 = (4-T) 2,
That is to say, △ PMC is an isosceles triangle when t = 0

First of all, if f (x + 1) is an odd function, then f (x + 1) is an odd function
F (x + 1) = - f [- (x + 1)] or F (x + 1) = - f (- x + 1)
Then answer me: if the function definition field is r, f (x + 1) and f (x-1) are both odd functions, then
F (x + 3) is an odd function
thank
c. F (x) = f (x + 2) d, f (x + 3) is an odd function

For example, if f (x + 1) = SiNx, then f (x + 1) = - f (- x + 1), not f (x + 1) = - f [- (x + 1)]. In fact, f (x + 1) is a composite function, but the independent variable is still X

The equation of the line perpendicular to the line 2x-y + 3 and the intercept on the x-axis is 2 larger than that on the y-axis is

The obtained line is perpendicular to the line 2x-y + 3 = 0 because the slope of the line 2x-y + 3 = 0 is 2,
So the slope of the straight line is - 1 / 2, so let the equation of the straight line be y = - 1 / 2x + B
Let x = 0, the intercept on the Y axis is B;
Let y = 0, the intercept on X axis is 2B;
According to the meaning of the title, 2b-b = 2, that is, B = 2
So the equation of the straight line is y = - 1 / 2x + 2, that is, x + 2y-4 = 0

What is the simple method of 2.8 * 1.1 + 9.9 * 0.8

=(2.8+9*0.8)*1.1
=10*1.1
=11

The straight line y = KX + B is parallel to the straight line y = 2-x / 3 and intersects with the straight line y = -- 2x + 1 / 3 at the same point on the y-axis

If the line y = KX + B is parallel to the line y = - 1 / 3 * x + 2, then k = - 1 / 3
The intersection of y = - 2x + 1 / 3 and Y axis is (0,1 / 3), so B = 1 / 3
So the analytical formula of the line is: y = - 1 / 3 * x + 1 / 3

Given x ＜ 5 / 4, find the maximum value of the function y = 4x-2 + 1 / (4x-5)
Given x > 0, Y > 0 and 1 / x + 9 / y = 1, find the minimum value of X + y

1) X ＜ 5 / 4 = = > 5-4x > 0y = 4x-2 + 1 / (4x-5) = 4x-5 + 1 / (4x-5) + 3 = - [5-4x + 1 / (5-4x)] + 35-4x + 1 / (5-4x) > = 2 √ (5-4x) * 1 / (5-4x2) = 2 (if and only if 5-4x = 1 / (5-4x) is equal sign) ymax = - 2 + 3 = 12) x + y = (x + y) * (1 / x + 9 / y) = 1 + 9x / y + Y / x = 10 + 9x / y + Y / x =