As shown in the figure, it is a big rectangle made up of five identical small rectangles. The perimeter of the big rectangle is 44 cm. Calculate the area of the big rectangle

As shown in the figure, it is a big rectangle made up of five identical small rectangles. The perimeter of the big rectangle is 44 cm. Calculate the area of the big rectangle

If the length of two small rectangles is equal to the width of three small rectangles, then the length of the small rectangle: width = 3:2, and the width is 23 of the length; if the length of the small rectangle is a centimeter, then the width of the small rectangle is 23a centimeter, and the length of the large rectangle is 2A centimeter; the width is a + 23a = 53a (centimeter); (2a + 53a) × 2 = 44, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2A + 53a = 22, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 113a=22，             A = 6; the length of a small rectangle is 6 cm, and the width is 6 × 23 = 4 (CM); the length of a large rectangle is twice the length of a small rectangle, and the width is the length and width of a small rectangle, so: the length of a large rectangle is 6 × 2 = 12 (CM), the width of a large rectangle is 4 + 6 = 10 (CM), and the area of a large rectangle is 12 × 10 = 120 (square cm). A: the area of this large rectangle is 120 square centimeters Rice

3000r/min=?rad/s

1R=2π
3000*2π=6000π
6000π/60=100π=314RAD/S

3 / x-3 / 5 = 5 - 5x-3 = 3 + 8x 1|5 (1 / 5) - 3x|5 = 1

3 x-3 5 = 5
X of 3 = 5 + 5 of 3
X of 3 = 20 of 3
X = 20 / 3 / 1 / 3
x＝20
-5x-3=3+8x
8x＋5x＝－3－3
13x＝－6
x＝－6÷13
X = - 6 / 13
1|5 (1 / 5) - 3x|5 = 1
(1 / 5-3 / 5) x = 1
- 2x of 5 = 1
X = 1 △ 2 / 5
X = - 5 / 2

The circumference of a square is 24 cm, and the side length of it is______ Cm

24 △ 4 = 6 (CM), so the answer is: 6

The velocity formula of physical point time

Vt/2=x/t=(V1+V2)/2
VT / 2 - velocity in the middle
V1, V2 are initial velocity and final velocity
X-displacement t-interval
It is only suitable for uniform motion

(m-2) x ^ 2Y ^ n + 1 is the quintic monomial of X, y and the coefficient is 1 to determine the value of M and n

m-2=1
2+(n+1)=5
m=3
n=2

A circular paper is cut into two sectors along the radius, and the ratio of the central angle of the circle is 3:4?
Why are the arc lengths of the two sectors cut along the radius when the ratio of the central angle of the two sectors is 3:4
8πr7
,
6πr7
All the others are clear, text description)

∵ the ratio of the center angle of the two sector is 3 ∶ 4
Their central angles are N1 = 3 × 360 & # 186; / 7 and N2 = 4 × 360 & # 186; / 7, respectively
Let the radius of the circle be r, which is obtained from the arc length formula L = n π R / 180
Then L1 = N1 π R / 180 = (3 × 360 & # 186; / 7) · π R / 180 = 6 π R / 7
L2=n2πr／180=﹙4×360º／7﹚·πr=8πr／7
∴

The denominator of a fraction is not the same, so it can not be added or subtracted directly. You should first convert () into a fraction with denominator () and then add or subtract

The denominator of a fraction is not the same, so it can't be added or subtracted directly. First (general score), the fraction with the same denominator can be added or subtracted

If real numbers x1, X2 satisfy | x1-x2 | = 3, then the variance of x1, X2 is equal to___ ．

Let the mean of x1, X2 be t = X1 + X22, then the variance of x1, X2: S2 = 12 [(x1-t) 2 + (x2-t) 2] = 12 [X12 + x22-2 (x1 + x2) t + 2t2], substituting t = X1 + X22 into the above formula, we can get: S2 = 14 (X12 + x22-2x1x2) = 14 (x1-x2) 2 = 14 | x1-x2 | 2 = 34, so the variance is 34

The radius of a circle is ACM. When the radius is increased by 5cm, the circumference of the circle is () cm and the area of the circle is () cm

The radius of a circle is ACM. When the radius of the circle is increased by 5cm, the circumference of the circle is (2a π + 10 π) cm, and the area of the circle is (a + 5) &# 178; π square cm