Solution equation: (2x + 3) + (X-7) (x + 6) = x & sup2; - 10 Solution equation: X (2x + 3) + (X-7) (x + 6) = x & sup2; - 10

Solution equation: (2x + 3) + (X-7) (x + 6) = x & sup2; - 10 Solution equation: X (2x + 3) + (X-7) (x + 6) = x & sup2; - 10

（2x+3)+（x-7)(x+6)=x²-10
2X + 3 + X ² - 7X + 6X - 42 = X² -10
X = 42-10-3
X = 29

It is known that one root of the equation 2x square minus 5x plus K is 1 (1) to find the value of K. (2) to solve this equation

1)
2x^2-5x+k=0
x=(5±√(5^2-4*2*k))/4=(5±√(25-8k))/4
x=1,√(25-8k)=1
25-8k=1
k=3
2) 2x^2-5x+3=0

It is known that the focus of the ellipse C: x2 / A2 + Y2 / B2 = 1 (a > b > 0) is on the x-axis, passing through the point P (- 8, - 2) to make the tangent of the circle x ^ 2 + y ^ 2 = 16, and the tangent points are a and B respectively
1. Find the equation of line ab,
2. If the line AB just passes through the left focus and the lower vertex of the ellipse, the standard equation of the ellipse is obtained

1. The center Q (0,0) of circle x ^ 2 + y ^ 2 = 16. The equation of circle with PQ as the diameter is: (x-0) (x + 8) + (y-0) (y + 2) = 0, that is, x ^ 2 + y ^ 2 + 8x + 2Y = 0 (1) circle Q: x ^ 2 + y ^ 2 = 16 (2) from the principle of curve system: (1) - (2) the equation of straight line AB is 4x + y + 8 = 02

The results are as follows: 1.98-32-28 2.156-19-81 3.217-65-135 4.345-66-345.205 + 87 + 136.398-163-137

1.98-32-28
=98-（32+28）
=98-60
=38
2.156-19-81
=156-（19+81）
=156-100
=56
3.217-65-135
=217-（65+135）
=217-200
=17
4.345-66-34
=345-（66+34）
=345-100
=245
5.205＋87＋13
=205+（87+13）
=205+100
=305
6.398-163-137
=398-（136+137）
=398-300
=98

8x-3=13,0.3x+0.4=0.7x-0.1,4x-5=9/2x-4 ,y-1/2+3=y+12/3-1

8X-3=13
8X=10
X=1.25
0.3X+0.4=0.7X-0.1
3X+4=7X-1
4X=5
X=1.25
4X-5=9/2X-4
8X-10=9X-8
X=-2
Y-1/2+3=Y+12/3-1
There is no solution to this problem

The focal point of an ellipse is on the x-axis. The distance ratio between one of its focal points and the two ends of the major axis is 1:4, and the length of the minor axis is 8

Let x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1
Because the short axis is 8
So 2B = 8
So B = 4
Because the ratio of the distance from one focus to the two ends of the long axis is 1:4
So (A-C): (a + C) = 1:4
So C = 3A / 5
And a ^ 2 = B ^ 2 + C ^ 2
So a ^ 2 = 16 + (3a / 5) ^ 2
So a = 5
So the equation is x ^ 2 / 25 + y ^ 2 / 16 = 1

Write the general term formula of sequence 1,2 / 3,3 / 5,4 / 7

An = n / (2n-1)

How much is 1 minus one sixth plus three fourths multiplied by minus 48 in brackets

（1-1/6）*（-48）=-5/6*48=-40

One fifteenth of eight tons is equal to a fraction of one ton
It can't be solved by equation

8×1/15=1×8/15
So one fifteenth of eight tons is eight fifteenth of one ton

When I need A3 > 5, the result is A3 * 0.15, and the formula is, = if (A35, 'A3 * 0.15))
Excle problem if formula problem
When I need A3 > 5, the result is A3 * 0.15
The formula is
=if（a35,'a3*0.15))

Gain and loss of right and wrong