If f (x) is an odd function defined on R and f (x + 1) = f (x-1), then f (1 / 2) + F (3 / 2) + F (5 / 2) + F (7 / 2) =?

If f (x) is an odd function defined on R and f (x + 1) = f (x-1), then f (1 / 2) + F (3 / 2) + F (5 / 2) + F (7 / 2) =?

If f (x) is an odd function defined on R, and f (x + 1) = f (x-1), then f (1 / 2) + F (3 / 2) + F (5 / 2) + F (7 / 2) =? F (x + 1) = f (x-1), which means that f (1 / 2) + F (3 / 2) + F (5 / 2) + F (7 / 2) = f (1 / 2) + F (- 1 / 2) + F (1 / 2) + F (1 / 2) = 3F 1 / 2) + F (- 1 / 2) (x) is an odd function defined on R

The interval of zero point of function f (x) = x2-2 is

I don't quite understand what you want
The zero point should be: x = positive and negative root sign 2

Find the linear equation which is parallel to the line 2x-y + 10 = 0 and whose intercept sum is only 2 on the x-axis and y-axis

Let X / A + Y / b = 1,
a+b=2,
-b/a=2,
The solution is a = - 2, B = 4,
The linear equation is: - X / 2 + Y / 4 = 1,
That is, 2x-y + 4 = 0,

Calculation of (- 5) x (+ 7 1 / 3) + + 7) x (- 7 1 / 3) - (+ 12) X7 1 / 3 by a simple method

(- 5) x (+ 7 / 3) + + 7) x (- 7 / 3) - (+ 12) X7 / 3
=-5x7 1 / 3-7x7 1 / 3-12x7 1 / 3
=-(5 + 7 + 12) X7 and 1 / 3
=-24x7 and 1 / 3
=-1 / 24x7-24x3
=-168-8
=-176

One more question
If the values of the algebraic formula x-2a + BX + 3 are always equal regardless of the value of X, find the values of a and B

x-2a+bx+3=ax+b
(1+b)x-2a+3=ax+b
No matter what the value of X is, the value of x-2a + BX + 3 and ax + B are always equal
The results are as follows:
1+b=a
-2a+3=b
The solution is: a = 4 / 3, B = 1 / 3

As shown in the figure, the straight lines y = - 3 / 4x + 6 and y = 3 / 4x-2 intersect point P. the straight lines y = - 3 / 4x + 6 intersect the x-axis, and the y-axis intersects the AB straight line y = 3 / 4x-2, and the y-axis intersects point C
Find the coordinates of the intersection of two straight lines
2 calculate the area of △ PCA

1. ∵ y = - 3 / 4x + 6 and y = 3 / 4x-2 intersect with point P.. The simultaneous solution of y = - 3 / 4x + 6 and y = 3 / 4x-2 gives x = 96 / 25, y = 128 / 25, that is, P (96 / 25128 / 25) 2, ∵ y = - 3 / 4x + 6 intersect with X axis at a, ∵ a (8,0) ∵ y = 3 / 4x-2 intersect with y axis at point C ∵ C (0, - 2) let the straight line passing through P and C be y = KX + B, then 128 / 25 = 96 / 2

If two functions satisfy f (a + x) = f (b-X), how to find the axis of symmetry of two functions?

Your expression is wrong. The conclusion is as follows:
1. If f (x) satisfies f (a + x) = f (b-X), then f (x) is symmetric with respect to the line x = (a + b) / 2
2. The functions y = f (a + x) and y = f (b-X) are symmetric with respect to the line x = (B-A) / 2

There are proverbs and poems about bridges, which are better to be different
The contents of the study plan of the bridge perspective map,

1. You take your Yangguan Road, I take my single wooden bridge. 2. A bridge flies north and south, and the natural moat becomes a thoroughfare. 3. Demolish the bridge across the river. 4. Return the bridge and return the road

It takes 2.56s for the radio wave to reach the moon and return to the earth. The propagation speed of the radio wave is
The distance between the earth and the moon is calculated when the radio wave propagates 3 × 10 km per second to the fifth power
Note: the radio wave propagates 3 × 10 km per second to the 5th power, and the result retains 2 significant digits.)

1. First, the distance of radio wave propagation is obtained: S = VT = 3 × 10 ^ 5km / s × 2.56s = 7.68 × 10 ^ 5km
2. Then the distance between the earth and the moon is calculated: s' = (1 / 2) s = (1 / 2) × 7.68 × 10 ^ 5 = 3.84 × 10 ^ 5km

The solution set (- 1 / 2,1 / 3) of inequality ax + BX + 2 > 0, then the value of A-B is equal to ()

The solution set of ax & # 178; + BX + 2 > 0 is (- 1 / 2,1 / 3), which shows that - 1 / 2 and 1 / 3 are the two roots of the equation AX & # 178; + BX + 2 = 0
Then - 1 / 2 + 1 / 3 = - B / A, - 1 / 2 × (1 / 3) = 2 / A
So a = - 12, B = - 2
So A-B = - 12 + 2 = - 10