Whose are these books?

Whose are these books?

Whose books are these?

[simple calculation] 1.56.7 * 23.4-567 * 1.26-108 * 4.67 2.11 * 91 + 209 * 998 + 627 3.998 * 563 + 8126

1. The original formula = 567x2.34-567x1.26-108x4.67 = 567x [2.34-1.26] - 108x4.67 = 567x1.08-1.08x467 = 1.08x [567-467] = 1.08x100 = 108
2. The original formula = 11 * 91 + 11 * 19 * 998 + 11 * 55 = 11 * [91 + 19 + 998 + 55] = 11 * 1163 = [10 + 1] * 1163
=10*1163+1*1163=11630+1163=12793
3. The original formula = [1000-2] * 563 + 8126 = 1000 * 563-2 * 563 + 8126 = 563000-1126 + 8126 = 563000 + 7000 = 570000

Ratio: 0.2:3 8.5:34 32:9 8
The result of reducing ratio is still a (), which is the simplest integer ratio; the result of calculating ratio is only a ()
() of 12 = 3 of 4 = 12: () = () (decimal in the last bracket)
375 = () of () = (): () = 16 ()

(9 out of 12) = 3 out of 4 = 12: (16) = (0.75) (fill in decimal in the last bracket)
375 = (1 of 8) = (1): (8) = 2 of 16

3 / 7, 1 / 2 and 7 / 12, 1 / 2, 3 / 4 and 5 / 8, 3 / 5, 5 / 8 and 7 / 12

3 / 7 = 36 / 84, 1 / 2 = 42 / 84, 7 / 12 = 49 / 84
So 3 out of 7 is less than 1 out of 2 and 7 out of 12
1 / 2 = 4 / 8 3 / 4 = 6 / 8 5 / 8
So 1 out of 2 is less than 5 out of 8 and 3 out of 4
3 / 5 = 72 / 120 5 / 8 = 75 / 120 7 / 12 = 70 / 120
So 7 out of 12 is less than 3 out of 5 and 5 out of 8

How to calculate 27.38-5.34 + 2.62-4.66 simply
also:
15.7-4.3+3.54+4.3
I want a simple formula

27.38-5.34+2.62-4.66=（27.38+2.62）-（5.34+4.66）=30-10=20
15.7-4.3+3.54+4.3=15.7+3.54+(4.3-4.3)=15.7+3.54=19.24

LIM (e ^ (1 / x)) / X (x tends to 0 -)

Let t = 1 / X
LIM (e ^ t * t) (t approaches negative infinity)
=LIM (T / e ^ (- t)) (t approaches negative infinity)
Using the law of lobita, we can get a better result
LIM (1 / e ^ (- t)) (t approaches negative infinity)
=0...
OK

Solving the equation B (b ^ 2-x ^ 2) = ax (A-X) - AB ^ 2 (a is not equal to b)

Calculation of 3.6 * 2.7 + 0.27 * 6.4 by simple method

3.6*2.7+0.27*6.4
=3.6*2.7+0.27*10*6.4
=(3.6+6.4)*2.7
=10*2.7
=27
I don't know, right? Look

If 9 ^ n · 27 ^ n + 1 △ 3 ^ 3N + 1 = 81, find the value of N - & sup2

If the a + 1 square of 2A + 1 power of 3 & sup2; × 9 △ 27 = 813 ^ 2 * 9 ^ (2a + 1) / 27 ^ (a + 1) = 813 ^ 2 * (3 ^ 2) ^ (2a + 1) / (3 ^ 3) ^ (a + 1) = 813 ^ 2 * 3 ^ (4a + 2) / 3 ^ (3a + 3) = 813 ^ (4a + 4) / 3 ^ (3a + 3) = 813 ^ (4a + 4-3a-3) = 813 ^ (a + 1) = 3 ^ 4A + 1 = 4A = 3

It is known that a and B are constants, and the difference between polynomial ax2-2xy + y and polynomial 3x2 + 2bxy + 3Y does not contain quadratic term, then (a + b) (a-b) = ()
A. 8b. - 8C. 4D. Uncertainty

Ax2-2xy + Y - (3x2 + 2bxy + 3Y) = (A-3) X2 - (2 + 2b) xy-2y, because there is no quadratic term in the result, so a = 3, B = - 1,... (a + b) (a-b) = 8