LG (x + 2) = 2y-2 What is the calculation process of LG (x + 2) = 2y-2 x = e ^ (2y-2) - 2 Note: e ^ (2y-2) means the power of 2y-2 of E What I don't know is how e ^ LG (x + 2) becomes x + 2 after taking logarithm on both sides at the same time, and how e and LG hedge (cancel) with that formula? rescue

LG (x + 2) = 2y-2 What is the calculation process of LG (x + 2) = 2y-2 x = e ^ (2y-2) - 2 Note: e ^ (2y-2) means the power of 2y-2 of E What I don't know is how e ^ LG (x + 2) becomes x + 2 after taking logarithm on both sides at the same time, and how e and LG hedge (cancel) with that formula? rescue

Take logarithm on both sides, e ^ LG (x + 2) = e ^ 2y-2
X + 2 = e ^ 2y-2, x = e ^ (2y-2) - 2, what do you don't understand?
It may be that the result of Ln (x + 2) = 2y-2 is x = e ^ (2y-2) - 2

VB expression: M = 67 / 3 mod 2.6 * fix (5.7) how to calculate?

The operation order of arithmetic operators is as follows:
^- (minus sign) * and / (integral Division) mod + and -&
fix(5.7)=5
So the expression M = 67 / 3 mod 2.6 * 5
=67/3 mod 13
=1

Which Three Gorges of the Yangtze River refers to?

The Three Gorges of the Yangtze River is one of the top 10 scenic spots in China and the top 40 tourist attractions in China. The Three Gorges of the Yangtze River is the general name of the Three Gorges of Qutang gorge, Wuxia gorge and Xiling Gorge. It starts from Baidi city in Fengjie, Sichuan Province in the West and ends at nanjinguan, Yichang, Hubei Province in the East, with a length of 204 km

The teacher gave a formula (1 + x) ^ α is the equivalent infinitesimal of α x, but he didn't say why he wanted to prove it
Same title

It is (1 + x) ^ α - 1 that is the equivalent infinitesimal of α x, but we can only prove the case of α = 1 / N or n (n is a positive integer). In general, we need to use the lobita's rule to prove it. Here we will give a hint of a case of proving α = n. as long as the limit of ((1 + x) ^ n-1) / NX is 1, we can use the formula x ^ n - 1 = (x-1)

There are 50 students in class 61. Boys account for 3 / 5 of the class. One third of the boys are good students. How many good students are there in class 61?
Think: ask how many good students there are among the boys, you can first find the number of () and the formula is (), and then find out how many good students there are among the boys, and the comprehensive formula is ()

50 times 3 / 5 = 30 (pieces) 30 times 1 / 3 = 10 (pieces)
So it's ten

A simple method is used to calculate the following questions: (90 + 1 / 88) * 1 / 89

（90+1/88）*1/89
=(89+89/88)*1/89
=89*1/89+89/88*1/89
=1+1/88
=89/88

In the arithmetic sequence with 2n + 1 terms, if the sum of all odd terms is 165 and the sum of all even terms is 150, then n is equal to ()
A. 9B. 10C. 11D. 12

From the odd number term and S1 = (n + 1) (a1 + A2N + 1) 2 = (n + 1) × 2An + 12 = (n + 1) an + 1 = 165, ① even number term and S2 = n (A2 + A2N) 2 = n × 2An + 12 = Nan + 1 = 150, ② n + 1n = 165150, the solution is n = 10

5 yuan 10 yuan 14 pieces, a total of 100 yuan, 5 yuan 10 yuan each several pieces
Column equation solution, remember Oh

X+Y=14 5X+10Y=100

Find the rule and fill in 1,3,4,7,7, ()
Such as the title

1,3,4,7,7,（14）

The sum of three consecutive natural numbers is denoted as a, followed by the sum of the following three natural numbers as B. can a multiply B by 111111111

Let three continuous natural numbers be x, x + 1, x + 2
The next three natural numbers are x + 3, x + 4 and X + 5
A=x+x+1+x+2
= 3x+3
B= x+3+x+4+x+5
= 3x+12
A.B = (3x+3)(3x+12) =111111111
=> 9(x+1)(x+4)=111111111
9x^2+45x-111111075 = 0
△ = (45)^2+4(9)(111111075) =4000000725 is not a square
X is not an integer
So it's impossible