The bottom of a cuboid is a square. Unfold the side of the cuboid and it is a square with side length of 8 cm. Calculate the volume of the cuboid

The bottom of a cuboid is a square. Unfold the side of the cuboid and it is a square with side length of 8 cm. Calculate the volume of the cuboid


Bottom length = 8 △ 4 = 2cm
Volume = 2 × 2 × 8 = 32 CC



A cuboid packing box, measuring 18 meters high from the inside, has a square with a side length of 8 cm on the bottom. A teacup is placed inside. What is the volume of the teacup?


Volume = 4 × 4 × 3.14 × 18 = 904.32 cm3



A cuboid with a square bottom has a side length of 8 cm and a volume of 448 cubic cm. What is the height and surface area of the cuboid?
Be right


The height of the cuboid
=448/(8*8)
=448/64
=7 cm
The surface area of this cuboid
=(8*8+8*7+8*7)*2
=176*2
=352 square centimeters



The side of a cuboid with a square bottom is expanded to be a square programmed as 8 cm. What are the surface area and volume of the cuboid?
Er... Accidentally raised the reward so high


I'm glad to answer your question
The height of the cuboid is 8 cm, the side length of the bottom is 2 cm, so the volume is 2 * 2 * 8 = 32 cubic cm, and the surface area is 4 * 2 * 8 + 2 * 2 = 72 square cm



Bivariate linear inequalities 3x + 4Y > 2 and 5y-8x


3x+4y>2 (1)
5y-8x-6(3)
(1) 15x + 32x > - 14 for * 5 + (3) * 4
x>-47/14
Y you should be able to



The reciprocal of one number is 24, and the reciprocal of the other number is 1 and 3 / 5. What is the sum of these two numbers?


The first number is 1 / 24
The reciprocal of the second number is written as the false fraction 8 / 5, which is 5 / 8
1/24+5/8=1/24+15/24=16/24=2/3



If 5x_ 6 y = 0, and XY is not equal to 0, then 5x_ 4Y divided by 5x_ The value of 3Y is equal to?


5x=6y
5x-4y=6y-4y=2y
5x-3y=6y-3y=3y
(5x-4y)/(5x-3y)=2y/3y=2/3



What is the minus two-thirds power of a?





If the value of fraction x + x-3 is 0, then x = ()


3, the denominator cannot be 0, so only the numerator x-3 = 0



Given that the vertex coordinates of the parabola y = x2 + BX + C are (1, - 3), then the values of b'c are:


y=x2+bx+c
=(x + B / 2) ^ 2 + C-B ^ 2 / 4
So the vertex coordinates are
(-b/2,c-b^2/4 )
Vertex coordinates are (1, - 3)
therefore
-b/2=1 c-b^2/4=-3
The solution is b = - 2, C = - 2