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Now there is an empty cuboid container a and a cuboid container B filled with water 24 cm deep. Pour part of the water in container B to a (supplement, bottom) Now there is an empty cuboid container a and a cuboid container B with 24 cm deep water. We need to pour part of the water in container B to container a, so that the water in the two containers is the same height. At this time, how many cm deep is container a? Urgent, want to segment formula, hope to have enthusiastic netizens to help (Note: container a is 40cm long, 20cm high and 30cm wide. Container B is 30cm long, 24cm high and 20cm wide.)
First of all, you need to know that the height of the known water is the same. If the phase height is x, then 40 * 30 * x + 30 * 20 * x = 24 * 30 * 20, you will know X
As shown in the figure, pour all the water in the cuboid with a height of 6.28 cm into the cylindrical container. At this time, how many cm is the water depth,
Cylinder, bottom radius 5 cm, height 20 cm, cuboid, length 10 cm, width 10 cm, height 6.28 cm,
10 * 10 * 6.28 ÷ (3.14 * 5 * 5) = 8 cm
A cuboid container, measured from the inside, has a bottom area of 200 square centimeters and a height of 30 centimeters. Pour 1 liter of water into the container to measure the depth of water______ Cm
1 liter = 1 cubic decimeter = 1000 cubic centimeter, 1000 △ 200 = 5 (CM), answer: the water depth in the container is 5 cm
As shown in the figure, the specification of small bulb is "6V & nbsp; The maximum value of the sliding rheostat is R. the power supply voltage and filament resistance remain unchanged (1) Calculate the resistance of the small bulb. (2) close the switch, move the slide of the sliding rheostat, so that when the resistance of the sliding rheostat is R4, the power of the bulb is P1; when the resistance of the sliding rheostat is r, the power of the bulb is P2. Given that p1p2 = 91, calculate the maximum resistance of the sliding rheostat R. (3) if the resistance of the sliding rheostat is R8, the power of the small bulb is P1 The bulb lights normally. Calculate the power supply voltage
(1) According to P = u2r, the resistance of small bulb: RL = ul2pl = (6V) 26W = 6 Ω; (2) when the resistance of sliding rheostat is R4, the electric power of bulb: P1 = i12rl, when the resistance of sliding rheostat is r, the electric power of bulb: P2 = i22rl, then p1p2 = i12rli22rl = (i1i2)
What is a composite column? (), 35, 63, 80, 99, 143 what is the first number?
The sum or sum sequence refers to the first n items of a sequence and the sequence as the nth item. The sum sequence may refer to the sequence composed of sum numbers. You can see the following. (positive integers that can be divided by 1 and other integers are called sum numbers, and those that can only be divided by 1 and themselves are called prime numbers, also called prime numbers)
Calculation of atmospheric pressure
A standard atmospheric pressure is 101000, which is equivalent to the pressure generated by the vertical pressure of 0.7kg object
Please write down the process and unit
F=G=mg=0.7×10=7N
P = f / S
So s = f / P = 7 / 1.01 × 10 ^ 5
≈6.93×10^-5m^3
≈69.3cm^3
Find the hyperbolic equation and eccentricity of a (23, − 3) which is a common asymptote with hyperbola x216 − Y29 = 1
Let the hyperbolic equation be: x216 − Y29 = λ (λ≠ 0) (3 points) and ∵ point a (23, − 3) on the hyperbola, ∵ λ = 1216 − 99 = − 14 (8 points) the hyperbolic equation is: x216 − Y29 = − 14, which is reduced to the standard form, and y294 − x24 = 1, thus A2 = 94, C2 = 94 + 4 = 254. Therefore, the eccentricity satisfies E2 = 25494 = 259, and the solution is e = 53 (12 points)
Ordinary led uses 12V power supply, how much resistance should be added?
I have a color changing diode (maybe 3V) in my hand. If I want to detect whether the 12V circuit is connected, how much resistance should I add in the middle?
The supply voltage (V) minus the diode voltage drop (V), and then divided by the current (a), is equal to the resistance (Ohm)
The working current of LED is about 10 Ma, so (12v-3v) / 0.01A = 900 ohm
In fact, it's not very strict to choose about 1000 euro. It's OK to choose between 500 and 5000 euro
The range of function f (x) = √ - X & # 178; + 2x + 8 is
-x²+2x+8
=-(x-1)²+9≤9
So 0 ≤√ (- X & # 178; + 2x + 8) ≤√ 9 = 3
So the range [0,3]
Comparison of power consumption of 50 lumen / W LED lamp and energy saving lamp
In terms of power consumption, 1W led and 1W energy saving lamp are the same
If it's a 50lm led, it's not as good as a good energy-saving lamp
Good quality energy-saving lamp, 1W luminous flux can reach 70-80lm
RELATED INFORMATIONS
- 1. A cuboid container, measured from the inside, has a bottom area of 200 square centimeters and a height of 30 centimeters. Pour 1 liter of water into the container to measure the depth of water______ Cm
- 2. A cuboid container, measured from the inside, has a bottom area of 200 square centimeters and a height of 30 centimeters. Pour 1 liter of water into the container to measure the depth of water______ Cm
- 3. A 150 cubic centimeter iron block is completely immersed in a cylindrical container containing water. The diameter of its bottom is 10 cm. How much has the water surface risen People's education sixth grade matching exercise book page 12
- 4. A cylindrical container with a bottom radius of 5cm is filled with water. Immerse a 157 cubic centimeter iron block in water. When the iron block is taken out, how many centimeters does the water surface drop?
- 5. If a 150 cubic centimeter iron block is completely immersed in a cylindrical container with water, and the bottom diameter of the cylindrical container is 10 cm, then Process to calculate What's the height of the rise of the water? (the number obtained keeps the whole number)
- 6. The cube container with the edge length of 6 decimeters is filled with water. Pour all the water in the container into a cuboid water tank. The water tank measures 6 decimeters long, 5 decimeters wide and 8.5 decimeters high from inside. At this time, what is the depth of water poured into the water tank? How many liters of water should I fill the tank?
- 7. (unit: cm) there is 1 long 15 wide 10 cuboid container with water. Put 4 eggs in it. The water rises by 2. There is a formula for calculating the volume of eggs. Thank you
- 8. The volume of an egg is measured with a cylindrical glass container and a conical glass container. It is known that there is the same amount of water in the two containers, and the area of the bottom of the cylinder The bottom radius of the cone container is 10 cm and the height is 20 cm. The water in the cone glass container is 12 cm high. Put the egg in the cone container and immerse it completely. The water level rises by 6 cm. Then put the egg in the cylinder container and immerse it completely. How many cm does the water rise?
- 9. The diameter of the bottom surface of a cylindrical container is 10 cm. After putting a piece of iron into the container, the water surface rises by 2 cm. The volume of this piece of iron is () cubic cm A. 157B. 628C. 125.6D. 78.5
- 10. A cuboid container with a bottom area of 15 square decimeters contains 3 decimeters of water. After an irregular stone is put into the container (the stone is completely immersed in the water, and the water surface rises by 2 cm). How many cubic decimeters is the volume of the stone?
- 11. A cuboid glass jar, measuring from the inside, 50 cm long, 40 cm wide and 20 cm high. Now pour 1 liter of water into the glass jar, and the water depth is 100 cm______ Cm
- 12. There is a cuboid glass container. The container measures 40cm long, 30cm wide and 35cm high from the inside. He injects some water into the container until the water depth is 10cm. Finally, he puts a cube iron block with 20cm edge length into the water and finds that the top of the iron block is still higher than the water surface. So, what is the water depth at this time?
- 13. It is known that the volume of a spherical iron block is measured by a rectangular container with a side length of 8 cm and a height of 16 cm It is known that a rectangular container with a side length of 8 cm on its bottom and a height of 16 cm is used to measure the thickness of the container Measure the volume of a spherical iron block. The water in the container is 2 cm away from the mouth of the cup In the container, some water overflows. When the iron block is taken out, the water surface drops by 5cm Product
- 14. A cuboid with a square bottom is 8 cm high. If its height is increased by 1 / 3, its surface area will be increased by 24 square cm（ emergency
- 15. A horizontal cuboid with a side length of 8 cm and a height of 3.5 cm is on the bottom. What is the surface area and volume of the cuboid?
- 16. The bottom of a cuboid is a square. Unfold the side of the cuboid and it is a square with side length of 8 cm. Calculate the volume of the cuboid
- 17. The volume of a cuboid is 192 square centimeters, the bottom is a square with side length of 8 centimeters, and the surface area of the cuboid is ()
- 18. Make a 5cm deep uncovered rectangular iron box with a 40cm long and 20cm wide rectangular iron sheet. What is the maximum volume of this iron box
- 19. A 40 cm long, 30 cm wide rectangular iron sheet, four corners minus a side length of 5 cm square, make a 5 cm deep uncovered rectangular iron box What's the volume of this iron box The thickness of iron sheet is not included
- 20. There is a rectangular sheet of iron 40 cm in length and 30 cm in width. Cut out an equal small square at its four corners to make a cuboid uncovered sheet iron box 5 cm in depth (the thickness of welding joint is not included). What is the volume of the box?