A cuboid container, measured from the inside, has a bottom area of 200 square centimeters and a height of 30 centimeters. Pour 1 liter of water into the container to measure the depth of water______ Cm

A cuboid container, measured from the inside, has a bottom area of 200 square centimeters and a height of 30 centimeters. Pour 1 liter of water into the container to measure the depth of water______ Cm


1 liter = 1 cubic decimeter = 1000 cubic centimeter, 1000 △ 200 = 5 (CM), answer: the water depth in the container is 5 cm



A cuboid container, measured from the inside, has a bottom area of 400 square centimeters and a height of 20 centimeters. Pour 1 liter of water into the container, with a depth of () cm?


1 liter of water = 1000 cubic centimeters
The bottom area is 400 square centimeters
Then 1 liter of water is poured into the container, and the water depth is 1000 △ 400 = 2.5 cm



A rectangular container with a bottom area of 200 square centimeters is 8 centimeters high and contains 4 centimeters of water. Now a stone is placed in a container (the stone is completely immersed)
A rectangular container with a bottom area of 200 square centimeters is 8 centimeters high, and there is 4 centimeters of water in it. Now put a stone into a container (the stone is completely immersed in water), and the water surface rises by 2 centimeters. How about the volume of the stone?


Is it possible to calculate the volume of the stone? If it is, there is one less condition in LZ, that is, the water surface rises by 2cm,
The answer is very simple: 200 * 2 = 400 (CM & # 179;)
I also hope LZ will complete the questions next time



Several computer problems
In the following statements about utilities, the error is_______________ .
A. The utility program completes some tasks related to the management of computer system resources and files
B. Some of the utilities are used to deal with various problems in the process of computer operation
C. Some of the utilities are designed to make it easier and more convenient for users to use the computer
D. The user program is independent of the operating system
In word, the following statement about the operation of tables is incorrect_______________ .
A. The text can be converted into a table
B. The table can be converted to text
C. The text and table can be converted to each other
D. The text and table cannot be converted to each other
3. In powerpoint2002, there are several ways to display views_______________ .
A. General, slide show, outline
B. General, slide show, slide show
C. General, slide show, outline
D. Slide view, slide show, outline
At present, in_______________ With the rapid development of information technology, the process of world informatization is speeding up
A.\x05Internet
B.\x05Nowell
C.\x05Windows NT
D.\x05ISDN


c d a a



If two identical "220 V & nbsp; 100 W" electric lamps are connected in series and then connected in 220 V circuit, the total electric power of the two lamps is ()
A. 200 WB. 100 WC. 50 WD. 25 W


When the voltage at both ends of a bulb is 220 V, the power is 100 W, that is, P = u2r = 100 W, ∵ the specifications of the two bulbs are the same, ∵ the resistance of the two bulbs are R, ∵ the total resistance in the series circuit is equal to the sum of the partial resistance, and the voltage of the power supply remains unchanged, ∵ when the two bulbs are connected in series in the 220 V circuit, the total electric power of the two lamps: P total = u2r + r = u22 r = 12, P = 12 × 100 W = 50 W



It can be easily calculated by dividing 11 / 15 + (2 / 3-3 / 5) by 1 / 4


11 / 15 + (2 / 3-3 / 5) divided by 1 / 4
=11/15+(10/15-1/15)x4
=11/15+4/15
=1



If the potential difference between a and B is 1 V, and an electron moves from a to B, the work done by the electron to overcome the electric field force is 1 eV, then ()
A. The electric potential energy of the electron increases by 1 eV D and the kinetic energy of the electron increases by 1 eV


A. The electric potential of a is higher than that of B, and the electric field strength has nothing to do with the electric potential, but the electric field strength does not necessarily point from a to B, and it is impossible for B to point to A. therefore, AB is all wrong. C. if the work done by the electron to overcome the electric field force is 1eV, then the electric potential energy of the electron increases 1eV. Therefore, C is correct. D. if the work done by the electron to overcome the electric field force is 1eV, according to the kinetic energy theorem, the kinetic energy decreases 1eV Error. So select C



Calculation (9915-16) × 8


(99 15\16)×8
=(100-1/16)×8
=800-½
=799.5



How many kilowatts of heat is a cubic meter of gas?


1 cubic meter of natural gas (2.1 yuan) heat = 10 degrees of electricity (5.5 yuan) heat. If a family uses 200 liters of hot water every day, we can see the cost
The water inlet temperature is 10 ℃ and heated to 45 ℃
The specific heat of water = 1 liter of water to 1 degree requires 1 kcal of heat
The heat required to heat 200 liters of water from 10 ℃ to 45 ℃ is
200 liters * 1 kcal / L * = 7000 kcal
The thermal efficiency of gas water heater is 85%
The minimum heat value of 〈 1 〉 1 cubic meter liquefied gas is 21000 kcal
The highest value is 28000 kcal and 25900 kcal in Jiangsu and Zhejiang
200 liters of water from 10 degrees to 45 degrees, the required liquefied gas is
7000 kcal / < 25900 kcal * 85% > is equal to 0.32 cubic meters
The cost of 1 cubic meter of liquefied gas is 9 yuan 5 yuan
It costs three yuan to heat 200 liters of water from 10 to 45 degrees
The minimum heat value of 〈 2 〉 1 cubic meter natural gas is 7100 kcal
The highest value is 12000 kcal, and the highest value is 9000 kcal in Jiangsu and Zhejiang
The amount of natural gas required to heat 200 liters of water from 10 ℃ to 45 ℃ is
7000 kcal / 9000 kcal * 85% is equal to 0.9 cubic meters
One cubic meter of natural gas costs 2 yuan 4 yuan
The cost of heating 200 liters of water from 10 ℃ to 45 ℃ is 2 yuan and 2 yuan
The thermal efficiency of electric water heater is 80%
The heat of 1 kwh is 860.42 kcal
200 liters of water is heated from 10 to 45 degrees. The electricity required is
7000 kcal / < 860.42 kcal * 80% > is equal to 10.2 degrees
5 cents per kilowatt hour
The cost of heating 200 liters of water from 10 to 45 degrees is $5.6



{x + y = 420,30% x + 40% y = 160 × 80% to solve the equation


x+y=420 (1)
30%x+40%y=160×80% (2)
The simplified formula (2) is as follows
3x+4y=1280 (3)
(1) 4 - (3)
x=400
Substituting (1), the solution is y = 20
By testing, x = 400, y = 20 are the solutions of the equations
Therefore, the solution of the equations is:
x=400
y=20