A cuboid with a square bottom is 8 cm high. If its height is increased by 1 / 3, its surface area will be increased by 24 square cm（ emergency

A cuboid with a square bottom is 8 cm high. If its height is increased by 1 / 3, its surface area will be increased by 24 square cm（ emergency

24÷（8×1/3）＝9
Side length of square: 9 △ 4 = 9 / 4
Volume: 9 / 4 × 9 / 4 × 8 = 81 / 2 = 40.5 cm3

The volume of the spherical iron block is measured in a cylindrical container with a bottom diameter of 8 cm and a height of 17 cm. The water in the container is 2 cm away from the cup mouth

(8? 2) = 351.68 cm3

If the solutions of the system {2x-y = 32kx + (K + 1) y = 10} are opposite to each other, then the value of K is equal to

Because the solution is the opposite,
Then x = - y,
It's 2x-y = 3,
We can get - 3Y = 3,
So y = - 1,
x=1.
Substituting x = 1, y = - 1 into 2kx + (K + 1) y = 10,
Then 2K - (K + 1) = 10,
So k = 11

What is the X-Power integral of E, a times the - X-Power integral of E?
Give me the basic integral formula, thank you

∫ e ^ xdx = e ^ x + C & nbsp; [this is the basic formula]
 
  ∫a·e^(-x)dx
=-∫a·e^(-x)d(-x)
=-a·e^(-x)+C
 
This problem uses the following formula (12)
 

In △ ABC, ab = 2, BC = 4, angle B = 60 °, let o be the center of the triangle ABC, if the vector Ao = PAB + QAC, then the value of P / Q is

Solution: AC ^ 2 = 2 ^ 2 + 4 ^ 2-2 * 2 * 4 * cos 60 ° = 12, AC = 2 √ 3,
2 ^ 2 + (2 √ 3) ^ 2 = 4 ^ 2, so ab ⊥ AC
Radius of inscribed circle r = (2 + 2 √ 3-4) / 2 = √ 3-1,
Let o be OE ⊥ AB, of ⊥ AC, and aeof be a square,
AE=AF=√3-1,AE/AB=(√3-1)/2, AF/AC=(√3-1)/2√3
AE=(√3-1)/2*AB, AF=(√3-1)/2√3*AC
Vector Ao = vector AE + vector AF = (√ 3-1) / 2 * vector AB + (√ 3-1) / 2 √ 3 * vector AC,
p/q=[(√3-1)/2]/[ (√3-1)/2√3]=√3

What is the relationship between limit and derivative?
In recent days, when learning advanced mathematics, the teacher always mentioned that limit is the basis of derivative. I can't see the connection between limit and derivative. What's the connection between them?

When the independent variable X of the function y = f (x) produces an increment Δ x at a point x0, the limit a of the ratio of the increment Δ y of the output value of the function to the increment Δ X of the independent variable when Δ x tends to 0 exists, a is the derivative at x0. From this definition, we can know that the derivative is derived from the limit
It can be written as follows:
f(x0)'=lim(x→x0）[f(x)-f(x0)]/(x-x0).

What is 0.06 times 2 plus 5x

X * 1.5x = (1 * 1.5) x = 1.5x 1.5x ^ 2 1.5x ^ 2

On the inequality of X, the solution set of which the square of MX - (2m-1) x + (m-1) is greater than or equal to 0 is a nonempty set

The solution set of inequality MX ^ 2 - (2m-1) x + (m-1) ≥ 0 is nonempty
(1) When m = 0
x-1≥0
X ≥ 1, nonempty, consistent
(2) When m < 0, the opening of parabola is downward
Discriminant Δ = (2m-1) ^ 2-4m (m-1) = 1 > 0
So it is obvious that the solution set of the inequality MX ^ 2 - (2m-1) x + (m-1) ≥ 0 is a nonempty set
(3) When m > 0, the positive solution set is nonempty
In conclusion, the range of M is r
If you don't understand, please hi me, I wish you a happy study!

Enko kk-105b calculator arctan how to calculate ah?

Arctan 1 = 45 ° input 1 → point red 2ndf → point Tan → 45 ° it seems that Hyp is written in the manual, which is wrong. I just figured out that the brand is Kenko, not enko

If f (x + 1 / x) = x & # 178; + 1 / 2 of X, find f (x)

F (x + 1 / x) = x & # 178; + 1 / X & # 178; = x & # 178; + 2 + 1 / X & # 178; - 2 = (x + 1 / x) & # 178; - 2
So f (x) = x & # 178; - 2
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