Given proposition p: x > 0, proposition q: x square > 0, then p is a, B and C of Q, and a + b > C is a, B and V Given the proposition p: x > 0 and the proposition q: x square > 0, then p is Q a. If B and C are three line segments, then a + b > C is that a, B and V can form a triangle Li Min is an 18-year-old college student

Given proposition p: x > 0, proposition q: x square > 0, then p is a, B and C of Q, and a + b > C is a, B and V Given the proposition p: x > 0 and the proposition q: x square > 0, then p is Q a. If B and C are three line segments, then a + b > C is that a, B and V can form a triangle Li Min is an 18-year-old college student


Sufficient and unnecessary conditions, necessary and insufficient conditions, neither sufficient nor necessary conditions



It is known that the proposition p: a = {x A-1 < x a + 1, X ∈ r}, and the proposition q: B = {the square of x-4x + 3 is greater than or equal to 0}. (1) if a ∩ B = empty set
Given the proposition p: a = {x A-1 < x a + 1, X ∈ r}, the proposition q: B = {the square of x-4x + 3 is greater than or equal to 0}. (1) if a ∩ B = empty set, a ∪ B = R, find the real number a
(2) If P is not a necessary condition for Q, find the real number a


(1) ∩ B = empty set, a ∪ B = R, B = (- ∞, 1] ∪ [3, + ∞)
∴ A=(1,3)
∴ a = 2
(2) ∵ Q → non-p
Ψ (- ∞, 1] ∪ [3, + ∞) contains (- ∞, A-1] ∪ [a + 1, + ∞)
∴ a-1≤1,a+1≥3
∴ a=2



Mother monkey picked 17 peaches and divided them into 2 / 1, 3 / 1 and 9 / 1?
You can't eat it before you divide it. You can't divide half of it


9, 6, 2, borrow one first, a total of 18, 2 / 1 is 9. 3 / 1 is 6, 9 / 1 is 2, and there is one to return. I think it should be 1 / 2, 1 / 3, 1 / 9



A fourth power B sixth power - a third power B sixth power =?


a⁴b^6-a³b^6
=a³b^6(a-1)



The distance from Neijiang to Chengdu on Chengyu road is 170 km. A car and a bus run from Neijiang and Chengdu at the same time. After one hour and 10 minutes, the car runs 20 km more than the bus when they meet. Suppose the average speed of the car and bus is x km and Y km / h, then the binary linear equation system is?





X-0.2: x-1.52-0.4 = 9:7,


X-0.2/X-1.52-0.4 =9/7
7(X-0.2)=9(X-1.52-0.4 )
9X-17.18=7X-1.4
2X=15.78
X=7.89



At the same time, a and B two cars leave each other from 1000km away, and they are 360km away when they are four hours away. At this speed, after a few hours, the two cars meet?
Good Samaritan, help me!


360 / ((1000-360) / 4) = 2, so we meet in two hours



When k = (), the solution of the equation 1-x + 2 / 4 = k-2x / 6 is 2014


Substituting x = 2014 into the equation
1-(2014+2)/4=(k-2×2014)/6
1-503=k/6-4028/6
-502×6=k-4028
k=4028-3012
k=1016



Haizhou and Banpu are 20 kilometers apart. A train of passenger cars and a train of freight cars run from Haizhou and Banpu at the same time. They meet 0.5 hours later. It is known that the speed ratio of passenger cars and freight cars is 3:2. The speed of passenger cars can be calculated


20 △ 0.5 = 40 (km), 3 + 2 = 5, 40 △ 5 × 3 = 24 (km); answer: the speed of the bus is 24 km per hour



Move the decimal point of a decimal one place to the right, and the number obtained is 8.55 larger than the original number. What is the original number? (little champion 5 goes to the fifth place.)


Original number: 8.55 ÷ (10-1) = 0.95