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Given the condition P: | x + 1 | > 2 and the condition Q: 5x-6 is greater than the square of X, what is the condition of its no proposition
|x+1|
The correct conclusion in the following is ()
A. When proposition p is true, proposition "P and Q" must be true. B. when proposition "P and Q" is true, proposition p must be true. C. when proposition "P and Q" is false, proposition p must be false. D. when proposition p is false, proposition "P and Q" may not be false
If a, P and Q are true, then "P and Q" is true, so a is wrong; if B is obviously true; if C is false, then q can be false, so C is wrong; if P and Q are true, then "P and Q" is true, so D is wrong
Write a mathematical proposition in the form of q if P, and judge what condition P is Q
P = > Q, P is a sufficient condition for Q
If there are two double digits A and B, 25 of a is equal to 14 of B, then what is the biggest difference between a and B______ ．
Because a × 25 = B × 14, so a: B = 14:25 = 5:8, because a, B two double digits, a number of 25, that a is a multiple of 5, and a, B is greater than or equal to 10, less than 99; b each maximum 12 is 12 × 8 = 96, and a = 12 × 5 = 60 (exactly a multiple of 5), so the maximum difference between a and B is 96-60 = 36
What is the third power of 300?
27000000
The 3-hour journey of a bus is 60% of the 4-hour journey of a car. The speed ratio of a bus to a car is ()
A. 4：3B. 4：5C. 5：4D. 3：4
(60% △ 3): (1 △ 4), = 20%: 25%, = 4:5; therefore, B
Application of mathematical problems in triangle ABC
In the triangle ABC, the bisector of known angle ABC and angle ACB intersects at point F, makes de parallel BC through point F, intersects AB at point D, intersects AC at point E, if BD + CE = 9, then the length of segment De is
The quantitative relationship among BD, CE and De is de = BD + CE. The reason is that BF and CF are bisectors of angles respectively. By using the definition of bisector of angles, two pairs of diagonal equivalences can be obtained. Then, by parallel de and BC, two pairs of internal stagger angles are equal. By equivalent substitution and equal angle pair equilateral, BD = DF and EC = Fe can be obtained. By equivalent substitution, de = DF + Fe can be proved
If ∵ BF is the bisector of ∵ ABC, CF is the bisector of ∵ ACB, ∵ DBF = FBC, ∵ ECF = FCB, ∵ de ∥ BC, ∵ DFB = FBC, ∵ EFC = FCB, ∵ DBF = DFB, ∵ EFC = ECF, ∵ BD = FD, EC = EF, then de = DF + Fe = BD + CE = 9
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The passenger cars and freight cars go from a and B to each other. It is only after 3 / 10 of the whole journey that the passenger cars leave from a and meet each other
The goods are 30 meters more than the passengers, and the speed ratio of the two cars is 5:3. The distance between the two cars is long
It's a mathematical solution, not an equation
1-3 / 10 = 7 / 10 trucks successively, how many parts of the whole journey are left
The speed ratio of passenger and freight cars is 5:3, so the 7 / 10 journey ratio of the whole journey is 5:3
Therefore: the whole journey: 7 / 10 * 5 / 8 = 7 / 16
The freight car runs 7 / 10 * 3 / 8 + 3 / 10 = 9 / 16
Whole journey: 30 / (9 / 16-7 / 16) = 240 km
Geometric significance of linear programming in high school mathematics
With intercept, what is the slope of the distance between two points?
·Area can be obtained by multiplying two vectors
·We can transform the problem of three-dimensional (or higher dimensional) into the problem of two-dimensional plane
The distance between the two places is 120km. Car a and car B drive in the same direction from the two places at the same time. Car a is in the front, traveling 36km per hour
The distance between the two places is 120km. Car a and car B drive in the same direction from the two places at the same time. Car a is in the front, 36km per hour. Car B is in the back. If car B wants to catch up with car a in 8 hours, how many km per hour should car B travel
Set the speed of vehicle B as X km / h
8X=8*36+120
8X=408
X=51
A: car B should travel 51 kilometers per hour
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