Judge the truth of the negation of proposition p: the square of (- 2) under the root sign = 2 Judge the truth of the negation of proposition p: the square of (- 2) under the root = - 2 The title was copied wrong just now sorry

Judge the truth of the negation of proposition p: the square of (- 2) under the root sign = 2 Judge the truth of the negation of proposition p: the square of (- 2) under the root = - 2 The title was copied wrong just now sorry


The square of (- 2) under the root = - 2 is a false proposition
So the negation of the square of (- 2) under the root sign = - 2 is a true proposition



Judge whether the following proposition is true or false. If it is true, please write the proof process. If it is false, please give a counter example
1. It is known that a, B and C are real numbers. If AC = BC, then a = B
2. The complement of an angle must be obtuse


The first false proposition, when C = 0, AC = BC, then a may not be equal to B
The second false, when the angle is obtuse, its complement is acute



If the following two propositions are true or false, please give counter examples. If they are true, please give proof
Proposition 1: "a triangle whose bisector of a triangle's corner is the center line on the opposite side is an isosceles triangle."
Proposition 2: "there are two congruent triangles with two sides and the height of one side corresponding to the same."


The true proposition is as follows: D is the midpoint of BC, ad bisection angle BAC extends ad, to point E, makes ad = De, connects CE, because ad = De, BD = CD, angle ADB = angle CDE (opposite vertex angle), so triangle abd and triangle ECD are congruent (opposite corner edge) so AB = CE, angle bad = angle CED, because ad bisection angle BAC, so angle bad = angle CAD, so angle CAD = angle CED, so AC = CE, so AC = AB, so triangle ABC is isosceles triangle; The right triangle abd and the right triangle abd are the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd are the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd are the right triangle abd and the right triangle abd and the right triangle abd and the right triangle abd; B \\\# 39; D \\\3535; the middle AB = A and ab = a \\\\\\\\\\\\\\\; C & # 39; is SAS, ABC and a & # 39; B & # 39; C & # 39; congruent



Simplify the square of (a-b) + the square of (A-C) + the square of (B-C)


(a-b)^2+(a-c)^2+(b-c)^2=a^2-2ab+b^2+a^2-2ac+c^2+b^2-2bc+c^2=2(a^2+b^2+c^2-ab-ac-bc)



Li Wei rides a motorcycle from his home to the railway station. If he travels 30 kilometers per hour, he will start 15 minutes earlier than the train. If he travels 18 kilometers per hour, he will leave 5 minutes later than the train. If Li Wei plans to arrive at the railway station 10 minutes before the train leaves, what is the speed of Li Wei's motorcycle at this time?


Boy, let's do our homework



Compare the size of √ 2014 - √ 2013, √ 2012 - √ 2011, explain the reason and ask for help


Comparison of the size of √ 2014 + √ 2013 and √ 2012 + √ 2011



There is a mountain road. When a car goes up the mountain, it travels 30 kilometers per hour. When it returns from the original road, it travels 50 kilometers per hour. How about the average speed of the car when it goes up and down the mountain?
It's before 9:00 tonight!


Average speed of car up and down hill: (1 + 1) / (1 / 30 + 1 / 50) = 37.5 (km / h)



If at least one of the three parabola y = x ^ 2 + 4ax-4a + 3, y = x ^ 2 + (A-1) x + A ^ 2, y = x ^ 2 + 2ax-2a has a common point with X axis, the value range of a is obtained
RT


The opposite of the problem: if three parabola y = x ^ 2 + 4ax-4a + 3, y = x ^ 2 + (A-1) x + A ^ 2, y = x ^ 2 + 2ax-2a have no common point with X axis,
Then the discriminant is less than 0, (4a) ^ 2-4 (3-4A)



How many liters of gasoline does a car use when driving 2 / 3 km? How many kilometers can a car drive when driving 1 km?


① 3 / 25 / 3 / 2
=3 / 25 × 2 / 3
=2 / 25 (L)



The range of (sin α - cos α) / (sin α + cos α)


(sinα-cosα)/(sinα+cosα)
=(tanα-1)/(tanα+1)
=(tanα-tanπ/4)/(1+tanαtanπ/4)
=tan(α-π/4)
Range (- ∞, + ∞)