It is known that a, B and C are nonzero rational numbers It is known that a, B and C are nonzero rational numbers The molecules are a + B + C + BC + AC + AB + ABC. These are molecules; The denominator is the absolute value of the numerator above Simplify them. The sign is the plus sign By 9:30 tonight, urgent! Before 10:00 The process should be clear and easy to understand!

It is known that a, B and C are nonzero rational numbers It is known that a, B and C are nonzero rational numbers The molecules are a + B + C + BC + AC + AB + ABC. These are molecules; The denominator is the absolute value of the numerator above Simplify them. The sign is the plus sign By 9:30 tonight, urgent! Before 10:00 The process should be clear and easy to understand!

If ABC is all positive, then 77 items are reduced to + 1 -------- if ABC is one positive and two negative, then the first three items of - 1 are reduced to one + 1,2 - 1, the fourth - sixth items are reduced to one + 1,2 - 1, the seventh items are reduced to - 1 -------- if ABC is two positive and one negative, then the first three items of - 1 are reduced to two + 1,1 - 1, the fourth - sixth items are reduced to one + 1,2 - 1, the seventh

Given the position of rational numbers a, B, C on the number axis, as shown in the figure, simplify | C-B | + | C-A | - | b-a|
B is on the left side of 0, C and a are on the right side of 0, a is bigger than C

B < 0, a > C > 0
Then solve the problem: | C-B | + | C-A | - | b-a|
=c-b+a-c-b-a
=-2b
If it's right,

It is known that rational numbers a, B and C are on the number axis (0 is the origin of the number axis). Please simplify: | a | - | a + B | + | C-A | + | B + C|
—a——b————0———c——→

It can be seen from the figure that: a

The corresponding points of rational numbers a, B and C on the number axis are shown in the figure, where 0 is the origin. Simplify the value of | a | - | a + B | + | C-A | + | B-C |
————a———b———————0————a————〉

According to the meaning of the title
a

Judgment: the key of statistical grouping is group distance and group number

The key of error statistics grouping is the selection of grouping flag

For a rational number, the following operation is defined: a * b = ab-b, then (- 3) * 4=

Because a * b = ab-b,
So (- 3) * 4
=(-3)×4-4
=12-4
=8

There are peach trees, pear trees and apple trees in the orchard. There are 70 peach trees, and pear trees account for 1 / 4 of the total number of fruit trees. The ratio of apple trees to the other two trees is 1:3. How many fruit trees are there in the orchard?

Taking the total number of fruit trees as 1, pear trees account for 1 / 4 of the total number of fruit trees, apple trees account for 1 / (1 + 3) of the total number of fruit trees
There are fruit trees in the orchard
70 ÷ [1-1 / 4-1 / (1 + 3)] = 140 (trees)
A: there are 140 fruit trees in the orchard

When a is a value, the operation result of x ^ 2 + ax + 1 (x ^ 2-3x + 2) does not contain x ^ 2 items

Isn't it? I'll be happy if I have this kind of question in the exam
(x ^ 2 + ax + 1) (x ^ 2-3x + 2) if you look at the formula, you will find that the x ^ 2 of the previous factor and the 2 of the following factor can get items like x ^ 2. By analogy, ax and - 3x can have items like x ^ 2, then 1 and x ^ 2 have items like x ^ 2, so you can get items like 2x ^ 2-3ax ^ 2 + x ^ 2. If their sum is 0, 3A = 3
So a = 1

There are 270 students in Grade 6 of sunshine primary school, one fifth of whom are boys, equal to one fourth of girls. How many boys and girls are there in Grade 6

1 / 5 divided by 1 / 4 equals 4 / 5, then 54 = 9270 9 = 30, male 30 times 5 equals 150, female 30 times 4 equals 120

(20052005*2006-20062006*2005)/908=?

Let 2005 = m, 2006 = 1 + M
Then 20052005 = 10001m
20062006=[10000(m+1)+m+1]=10001(m+1)
Original formula = [10001m * (M + 1) - 100001 (M + 1) * M] / 908
=0/908=0