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PEP seventh grade volume II English word list, urgent 、、
The passenger car and the freight car travel from the two places at the same time. When they meet, the passenger car travels 60 kilometers more than the freight car. It is known that the speed ratio of the passenger car and the freight car is 5; 4. How many kilometers is the distance between the two places?
Same time, speed ratio equals distance ratio!
60 / (5 / 9-4 / 9) = 60 / (1 / 9) = 540km
Given a (3,5, - 70B (- 2,4,30), then the projective length of line AB on the coordinate plane YOZ is
100
A and B travel from two places 36 kilometers apart. If a walks 2 hours ahead of B, they meet after B starts 2.5 hours; if B walks 2 hours ahead of a, they meet after a starts 3 hours. How many kilometers do a and B walk each hour?
Let the velocities of a and B be respectively X and Y km / h. according to the meaning of the question, we can get: (2.5 + 2) x + 2.5Y = 363x + (3 + 2) y = 36. The solution is: x = 6y = 3.6. The velocity of a is 6 km / h, and that of B is 3.6 km / h
The square of (a + B + C) - (a-b-c) is factorized
(a+b+c)^2-(a-b-c)^2
=[(a+b+c)+(a-b-c)][(a+b+c)-(a-b-c)]
=2a*(2b+2c)
=4a(b+c)
Li Wei rides a motorcycle from his home to the railway station. If he travels 30km per hour, it will be 15min earlier than the train starts. If he travels 18km per hour, it will be 15min later than the train starts. When he arrives at the railway station 10 minutes before the train starts, what is the speed of his motorcycle?
First of all, we hold the hidden condition that the distance from Li Weijia to the railway station is certain, and set the distance as X km
If you travel 30km per hour, it will be 15min earlier than the train's departure time; if you travel 18km per hour, it will be 15min later than the train's departure time. That is to say, if you travel 30km / h, it will be 30min (0.5h) earlier than 18km / h, there will be
X/30=X/18-0.5
X/5=X/3-3
2X/15=3
X=45/2
That is to say, it is 45 / 2km from Li Wei's home to the station. At this time, it can be calculated from the condition that "if you travel 30km per hour, it will be 15min earlier than the train's departure time". Now there is still a long way to go before the train's departure
45 / 2 * 1 / 30 + 0.25 = 1 (hour)
Arrive at the railway station 10 minutes before driving, that is to say, walk 45 / 2 kilometers in 50 minutes
50 minutes is 5 / 6 hours
45/2*6/5=27KM/H
So the speed of his motorcycle should be 27 km / h
The calculation above is right until x = 60, but there is no unit for minutes and hours, so the final result is incorrect
A2 + 5a-2a2-3a2-5a-1 where a = - half
There are also X & # 178; + 4x-2x & # 178; - 5x + 3x & # 178; - 2, where x = 2
3pq-5 / 4m-4pq, where M = 5, P = 1 / 3, q = - 3 / 2
2X & # 178; - x-4 + 3x-4 & # 178;, where x = - half
evaluation
This paper is going to be a-5a-2a, and then it will be a; (5a-2a-2a, and; (5a-5a-2a) and; (5a-5a-2a, and will be 178; (; (5a-5a-2a; and-3a-3a; (5a-5a-2a; and-3a-178; (5a-3a-3a-178;; -3a-5a-5a-5a-2a, and will be 178; (5a-5a-5a-5a-2a, and will be 178; (5a-3a-3a-178; (; (5a-5a-5a-5a-5a-5a-178; and will be 178; (; (5a-5a-5a-5a-5a-5a-5a-2a-178; (feature feature feature feature feature feature 178; (5a-5a-5a-5a-5a-5a-5a-2a-2a-178; (; (\\\\\\\\\\\\\(?) 178; + 3x (?) 178;) + (4x-5x) - 2 = 2x (?) 178; - X-2 = 2 ×
When a train goes from place a to place B at the speed of 40 ㎞ per hour, it takes 20% less time to return. How many kilometers per hour does it take to return?
50 kilometers per hour
First simplify, then evaluate: (4A's square-3a) - (2a's square + A-1) + (2-A's square + 4a) fill in the blanks: when y = 1, 2Y's square + 6y-
First simplify, then evaluate: (4A's square-3a) - (2a's square + A-1) + (2-A's square + 4a)
Fill in the blanks: when y = 1, the square of 2Y + the square of 6y-3y-5y =?
Wrong number, when y = - 1
: (square of 4a-3a) - (square of 2A + A-1) + (square of 2-A + 4a)
=4a²-3a-2a²-a+a+2-a²+4a
=a²+a+2
2Y squared + 6y-3y squared - 5Y = - Y & # 178; + y = - 1 + 1 = 0
A car from a to B, the first hour to complete the whole 25%, the second hour to complete the whole 90 kilometers, from B there are still 9 / 20 of the whole
I don't have any money because I'm a novice
Let the whole process be X
X=25%X+90+9/20X
X-25% X-9 / 20x = 90
（100X-25X-45X）/100=90
30X=9000
X = 300 (km)
300 km
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