It is known that the length of the base of the isosceles triangle ABC is 10cm and the vertex angle is 120 degrees. Find the diameter of its circumscribed circle

The radius of circumscribed circle is the length of AB, ab = 5 △ sin60 ° = 10 √ 3 / 3, so the diameter of circumscribed circle is 20 √ 3 / 3

It is known that the isosceles triangle ABC is inscribed on the circle O with radius 5. If the length of the bottom edge BC is 6, then the tangent of the bottom angle is 0
I only have one answer, and the other one is not, in the case of obtuse isosceles triangle

As shown in the figure, Ao = Bo = co = 5BC = 6, D is the midpoint of BC, so BD = 3. According to the properties of isosceles triangle, ad is perpendicular to the collinear of BC, a, O and D. therefore, according to Pythagorean theorem, OD = 4, so ad = 5 + 4 = 9tan & lt; ABC = ad / BD = 9 / 3 = 3

It is known that the isosceles △ ABC is inscribed in ⊙ o with radius 5. If the length of the bottom edge BC is 6, then the tangent of the bottom angle is___ ．

As shown in figure (1), we can get ad = OA + od = 9, Tan ∠ abd = addd = 93 = 3. As shown in figure (2), we can get ad = oa-od = 1, Tan ∠ abd = addd = 13. To sum up, Tan ∠ abd = 3 or 13

It is known that the isosceles △ ABC is inscribed in ⊙ o with radius 5. If the length of the bottom edge BC is 6, then the tangent of the bottom angle is___ ．

As shown in figure (1), we can get ad = OA + od = 9, Tan ∠ abd = addd = 93 = 3. As shown in figure (2), we can get ad = oa-od = 1, Tan ∠ abd = addd = 13. To sum up, Tan ∠ abd = 3 or 13

It is known that the length of the base of the isosceles triangle ABC is 10cm and the vertex angle is 120 degrees. Find the diameter of its circumscribed circle