In △ ABC, ab = 5cm, BC = 7cm, AC = 8cm. Draw three circles with a, B, C as the center respectively, and make them circumscribed, then the radius of ⊙ A is cm, In △ ABC, ab = 5cm, BC = 7cm, AC = 8cm. Draw three circles with a, B, C as the center, and make them two outside Then the radius of ⊙ A is cm, the radius of ⊙ B is cm, and the radius of ⊙ C is cm

In △ ABC, ab = 5cm, BC = 7cm, AC = 8cm. Draw three circles with a, B, C as the center respectively, and make them circumscribed, then the radius of ⊙ A is cm, In △ ABC, ab = 5cm, BC = 7cm, AC = 8cm. Draw three circles with a, B, C as the center, and make them two outside Then the radius of ⊙ A is cm, the radius of ⊙ B is cm, and the radius of ⊙ C is cm

Let ⊙ a be the radius of a ⊙ B be the radius of B ⊙ C be the radius of C
AC=a+c=8 (1)
AB=a+b=5 (2)
BC=b+c=7 (3)
(1) - (2) get
c-b=3 (4)
(4) + (3) get
2c=10
c=5
Substituting (4)
b=2
B = 2 is substituted by (2)
a=3
Then ⊙ a radius is 3cm ⊙ B radius is 2cm ⊙ C radius is 5cm

In △ ABC, ab = 5cm, AC = 4cm, BC = 3cm, take a as the center and 3cm as the radius to draw circle a, then in the three sides of triangle ABC, the side that is tangent to circle a ---, the tangent point is----

Edge AC point C

As shown in the figure, in the RT triangle ABC, angle c = 90 degrees, angle B = 60 degrees, ab = 10cm, and the midpoint of AB is d. now take point C as the center of the circle and 5cm as the radius to draw circle C
Q: which of a, B and D are on circle C? Please explain why

Because angle c = 90 degrees, angle B = 60 degrees, ab = 10 degrees
So CB = 10 * cos60 = 5
CA = 10 * sin60 = 5 and radical 3
Because ad = DB = 10 / 2 = 5, the triangle DCB is an equilateral triangle, so CD = 5
r=CB=CD=5
So in D, B, C