Given the isosceles triangle ABC, the base BC = 20, D is a point on AB, and CD = 16, BD = 12, find the length of AD

In △ BCD, △ BCD is a right triangle from 122 + 162 = 202. Let ad = x, then AC = 12 + X, X2 + 162 = (x + 12) 2 from Pythagorean theorem, and the solution is x = 143

An isosceles triangle is 12 cm long at the bottom and 18 cm long at the top. Find the side length of the inscribed square of the triangle

Let the side length of the inscribed square be 2x, and draw the triangle and the height on the bottom,
The equation can be listed as follows
(6-x)/2x=12/2/18
x=3.6cm
2x=7.2cm

Given the isosceles triangle ABC, the base BC = 20, D is a point on AB, and CD = 16, BD = 12, find the length of AD

In △ BCD, △ BCD is a right triangle from 122 + 162 = 202. Let ad = x, then AC = 12 + X, X2 + 162 = (x + 12) 2 from Pythagorean theorem, and the solution is x = 143

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