In the known triangle ABC, ad is the middle line. Prove AD & # 178; = (1 / 2) (AB & # 178; + AC & # 178;) - (BC / 2) &# 178;

In the known triangle ABC, ad is the middle line. Prove AD & # 178; = (1 / 2) (AB & # 178; + AC & # 178;) - (BC / 2) &# 178;


It is proved that: according to the cosine theorem BC * BC = AB * AB + AC * ac-2ab * accos ∠ cab, ① ad * ad = AC * AC + CD * cd-2ac * CDCOS ∠ ACD, ② CD = AB, ∠ ACD = 180 ° - cab, so the formula can be changed into: ad * ad = AB * AB + AC * AC + 2Ab * accos ∠ cab, ③ ① + ③, that is: 2 (AC * AC + CD * CD) = ad * ad