If LAL + LBL = 0, then LAL = (), LBL = () There's another question! LAL () 0

If LAL + LBL = 0, then LAL = (), LBL = () There's another question! LAL () 0

Because of the absolute value
|a|≥0,|b|≥0
Let | a | + | B | = 0 hold
If and only if | a | = 0, | B | = 0, the equation can be zero!
So | a | = 0, | B | = 0
Obviously, the discussion of | a | ≥ 0 can be divided into three categories (a > 0, a > 0)

Vector a = b.lal × LBL = 2lbl squared

|A | * | B | = 2 | B | ^ 2, that is: | a | = 2 | B |, how can there be: a = B? Unless | B | = 0, then a and B are both zero vectors
The title is incomplete, please clarify