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The rational numbers a, B and C are not 0. Let x = molecule a | a | + molecule B | B | + molecule C | C |, and find the value of the algebraic formula x square + 99x + 2011
When a, B, C are less than 0, x = - 1-1-1 = - 3, the original formula = 9-297 + 2011 = 1723; when two numbers in a, B, C are less than 0, x = 1-1-1 = - 1, the original formula = 1-99 + 2011 = 1913; when two numbers in a, B, C are greater than 0, x = 1 + 1-1 = 1, the original formula = 1 + 99 + 2011 = 2111; when a, B, C are greater than 0, x = 1 + 1 + 1 = 3, the original formula = 9 + 297 + 2011 =
The rational numbers a, B and C are not zero. Let x = absolute value of a + absolute value of B + absolute value of C, and find the square of the algebraic formula x + 99x + 2012=
When a, B and C are all positive numbers, x = 3 x & # 178; + 99x + 2012 = 3 & # 178; + 99 × 3 + 2012 = 2318 when a is negative, B and C are positive or B are negative, a and C are positive or C are negative, a and B are positive, x = 1 x & # 178; + 99x + 2012 = 1 & # 178; + 99 × 1 + 2012 = 2112
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