A Y, yn connection, 560kva, 10000 / 400V three-phase transformer is specially used for lighting. If the incandescent lamp is 100W, 220V, how many lamps can be connected to the three-phase? The solution is very simple, Sn / P = n, do you have a good idea? I still don't understand the meaning of the problem. If the lamp is connected to the secondary side, it must be connected to the secondary side, as long as the total rated current of the lamp is connected, It's OK to reach the required current of the secondary side, but it's different from the answer. The answer is 5600

A Y, yn connection, 560kva, 10000 / 400V three-phase transformer is specially used for lighting. If the incandescent lamp is 100W, 220V, how many lamps can be connected to the three-phase? The solution is very simple, Sn / P = n, do you have a good idea? I still don't understand the meaning of the problem. If the lamp is connected to the secondary side, it must be connected to the secondary side, as long as the total rated current of the lamp is connected, It's OK to reach the required current of the secondary side, but it's different from the answer. The answer is 5600

The power factor of incandescent lamp is 1, so it is not necessary to consider the power factor in calculation. When the power factor is 1, 560kva can bring 560kw equipment. According to the law of conservation of energy: a lamp 100kW, 560kva transformer can only bring 5600 lamps

Zhang Hua's family has a lighting lamp marked with "220V 100W". In order to save electricity, she connected a constant resistance in series to the lamp, so that the actual voltage of the lamp is 50% of the rated voltage. At this time, the actual power of the lamp is

Voltage of bulb U1 = 50% u = 220 * 50% = 110V
Bulb resistance (regardless of temperature) r = UU / P = 220 * 220 / 100 = 484 ohm
At this time, the actual power P (real) = u1u1 / r = 110 * 110 / 484 = 25W