In the circuit with 2.4kw power and 220 V supply voltage, the fuse with 6 a fusing current can be selected______ (judge right or wrong)

According to P = UI, I = Pu = 2.4 × 103w220v ≈ 10.9A, the current in the circuit is 10.9A, which is greater than the fuse's fusing current 6a, so the fuse with fusing current 6A cannot be selected

An electric appliance is connected to a 220 V power supply, the current is 0.6 a, and its electric power is () if it is electrified for 10 minutes, the current does work () J

P = UI = 220V x 0.6A = 132W, w = Pt = 132W x (10 x 60) s = 79200j

When a consumer is connected to a power supply with constant voltage, its power consumption is p; if the consumer is connected to the same power supply with a long wire
The electric power consumed is p '; then the expression of the electric power consumed on the conductor is P line =_____ W.

Let the supply voltage be u, the resistance of the consumer be r, and the resistance of the long wire in the following case be R1
When the consumer is directly connected to the power supply with constant voltage, P = u ^ 2 / R. equation 1
When the consumer is connected to the same power supply with a long wire, the current in the circuit is I = u / (R + R1)
In this case, the power consumption of the consumer is p '= I ^ 2 * r = [U / (R + R1)] ^ 2 * r. equation 2
The power consumption on long conductor is P line = I ^ 2 * R1 = [U / (R + R1)] ^ 2 * R1. Equation 3
From equations 1 and 2, P / P '= (R + R1) ^ 2 / R ^ 2 = [1 + (R1 / R)] ^ 2
According to equations 2 and 3, P line / P '= R1 / R
So p / P '= [1 + (P line / P')] ^ 2
The calculated power consumption of long conductor is P line = [root (p * p ')] - p'

In the circuit with 2.4kw power and 220 V supply voltage, the fuse with 6 a fusing current can be selected______ (judge right or wrong)